題目描述

當你學一些可視化程序設計語言時，老師經常會讓你設計并且編程做出一個計算器，這時也許你會仿照windows系統(tǒng)自帶的計算器外觀和功能去設計，但是現(xiàn)在老師要你多做出一個有新功能的計算器，實現(xiàn)當輸入一個數時，能夠將這個數分解成一個或多個素因子乘積的形式，并按素因子的大小排列顯示出來。大家對計算器中數的表示應該很清楚的。下面顯示出了0 — 9這十個數字的表示形式。每個數字都占據5 * 3大小的字符區(qū)域

你能實現(xiàn)這個新功能嗎？試試看吧！

輸入

輸入有多組測試數據，每組包括一個正整數n(1 < n <= 1000000)。

樣例輸入

10

2

輸出

對于每個數，將它分解成若干個素數乘積的形式，并按從小到大的順序輸出，素因子之間用“ * ”的形式連接。

樣例輸出

-???? -

|?? |

-? *? -

|?????? |

-???? -

-

|

-

|

-

解題思路：做這個題目做的第一步就是將一個整數分解為素數相乘的形式，以前學過，但是已經忘的差不多，這就算是重新溫習一下吧。做這個題目，說實話，思路很簡單，但是實現(xiàn)起來比較麻煩。這個題目需要注意的地方還有：素數可能是一個大于10的數，這時候需要進行分解，分解的過程中我用到了棧，先進先出，正好符合題目的輸出規(guī)則。

這個題目還有注意的地方(有點操蛋)，就是數字1的輸出，兩個"|"是在5x3的最后一列，剛開始我把它放中間了，然后交上去，wa，改了之后，直接AC了，唉~~~

代碼：

import java.util.*;

public class Main {

public static void printChar(int k,int num){

String[] line1 = {" - "," "," - "," - "," "," - "," - "," - "," - "," - "," "};

String[] line2 = {"| |"," |"," |"," |","| |","| ","| "," |","| |","| |"," "};

String[] line3 = {" "," "," - "," - "," - "," - "," - "," "," - "," - ","*"};

String[] line4 = {"| |"," |","| "," |"," |"," |","| |"," |","| |"," |"," "};

String[] line5 = {" - "," "," - "," - "," "," - "," - "," "," - "," - "," "};

switch (k){

case 0:

System.out.print(line1[num]);

break;

case 1:

System.out.print(line2[num]);

break;

case 2:

System.out.print(line3[num]);

break;

case 3:

System.out.print(line4[num]);

break;

case 4:

System.out.print(line5[num]);

break;

default:

break;

}

}

public static void main(String[] args) {

Scanner sc = new Scanner(System.in);

while(sc.hasNext()){

int n = sc.nextInt();

ArrayList list = new ArrayList<>();

int count = 0;

int tmp = n;

for(int i=2;i<=tmp;) {

if (tmp % i == 0) {

if(i>10){

int num = i;

Stack s = new Stack();

while(num>0){

s.push(num%10);

num/=10;

}

list.add(s.pop());

while(!s.empty()){

list.add(s.pop());

}

}else{

list.add(i);

}

list.add(10);

tmp /= i;

i = 2;

count++;

} else {

i++;

}

}

//System.out.println(count);

for(int k = 0;k<5;k++){

for(int i=0;i

//System.out.println(list.get(i));

printChar(k,list.get(i));

}

System.out.println();

}

}

}

}

總結

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