日韩av黄I国产麻豆传媒I国产91av视频在线观看I日韩一区二区三区在线看I美女国产在线I麻豆视频国产在线观看I成人黄色短片

歡迎訪問 生活随笔!

生活随笔

當前位置: 首頁 >

java long.max_value,Long + Long不大于Long.MAX_VALUE

發布時間:2024/9/27 39 豆豆
生活随笔 收集整理的這篇文章主要介紹了 java long.max_value,Long + Long不大于Long.MAX_VALUE 小編覺得挺不錯的,現在分享給大家,幫大家做個參考.

If I have an assignment

Long c = a + b;

Is there an easy way to check that a + b is not bigger/smaller than Long.MAX_VALUE/Long.MIN_VALUE?

解決方案

Using Guava, it's as simple as

long c = LongMath.checkedAdd(a, b); // throws an ArithmeticException on overflow

which is, I'd like to think, very readable indeed. (LongMath Javadoc here.)

For the sake of fairness, I'll mention that Apache Commons provides ArithmeticUtils.addAndCheck(long, long).

If you want to know how they work, well, the answer is one line of bit-hackery for Guava: the result doesn't overflow if (a ^ b) < 0 | (a ^ (a + b)) >= 0. This is based on the trick that the bitwise XOR of two numbers is nonnegative iff they have the same sign.

So (a ^ b) < 0 is true if a and b have different signs, and if that's the case it'll never overflow. Or, if (a ^ (a + b)) >= 0, then a + b has the same sign as a, so it didn't overflow and become negative.

(For more tricks like this, investigate the lovely book Hacker's Delight.)

Apache uses more complicated casework based on the sign of a and b.

總結

以上是生活随笔為你收集整理的java long.max_value,Long + Long不大于Long.MAX_VALUE的全部內容,希望文章能夠幫你解決所遇到的問題。

如果覺得生活随笔網站內容還不錯,歡迎將生活随笔推薦給好友。