《量化投資以python為工具》第九章作業第二題P109
輸入用戶名：首位必須為字母
輸入密碼：1.首位為字母
2.長度大于6
3.必須至少含有’_’或’*’或’#’中的一個
4.必須至少含有一個數字
代碼實現：

#方法一 def createuser():fuhao = ['_', '*', '#']while(1):print('input username:')username = input()if username[0] > 'a' and username[0] < 'z':breakelse:print('username must begin with a-z')while(1):print('input password:')password = input()if password[0] < 'a' or password[0] > 'z':print('password must begin with a-z')elif(len(password) <= 6):print('the length of password must upper 6')elif((fuhao[0] not in password) and (fuhao[1] not in password) \and (fuhao[2] not in password)):print('''password must at least include one of '_', '*', '#' ''')elif(('0' not in password) and ('1' not in password) and ('2' not in\password) and ('3' not in password) and ('4' not in password) and\('5' not in password) and ('6' not in password) and ('7' not in\password) and ('8' not in password) and ('9' not in password)):print('password must at least one number')else:print('create successful!')break #方法二 def createuser2():fuhao = ['_', '*', '#']while(1):print('input username:')username = input()if username[0] > 'a' and username[0] < 'z':breakelse:print('username must begin with a-z')while(1):print('input password:')password = input()if len(password) <= 6:print('the leghth of password must bigger than 6')err1 = 0err2 = 0for i in range(len(password)):if i == 0:if password[i] < 'a' or password[i] > 'z':print('password must begin with a-z')if password[i] in fuhao:err1 = 1if password[i] >= '0' and password[i] <= '9':err2 = 1if err1 == 0:print("""password must include at least one of '_', '*', '#'""")elif err2 == 0:print('password must at least include one of number')else:print('create successful!')break

沒有考慮大寫字母（懶得考慮了，也簡單，先將用戶名和密碼用lower()全部改為小寫字母再判斷就行）
之所以寫的這么麻煩是因為想要得到輸入具體不符合哪個要求。代碼有些冗余，大家隨時可以批評指正。

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