將整個故障單添加到結果列表中,而不只是優先級,然后實施您自己的min函數.另外,根據您的應用程序的其余部分,是否考慮使用與設置結果不同的結構？

# this computes the minimum priority of a ticket

def ticketMin (list):

min = list[0]

for ticket in list:

if (ticket.priority < min.priority):

min = ticket

return min

# changed set to list

result = list()

for ticket in tickets:

# to get rid of the "None" priorities

if ticket.priority != '':

print ""

else:

#notice the change below

result.append(ticket)

# changed 'min' to 'ticketMin'

minTicket = ticketMin(result)

print minTicket.priority

print minTicket.code

另外,您可以保存幾行,并將內置函數與Lambda一起使用,如Oscar在注釋中所示：

# changed set to list

result = list()

for ticket in tickets:

# to get rid of the "None" priorities

if ticket.priority != '':

print ""

else:

#notice the change below

result.append(ticket)

# Oscar's solution:

minTicket = min(result, key=lambda val : val.priority)

print minTicket.priority

print minTicket.code

總結

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