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Java简易井字棋

發布時間:2024/9/30 java 35 豆豆
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輸入三行三列數字,例如:
0 0 0
1 0 0
0 0 1
其中,0代表O,1代表X。

代碼運行邏輯: 檢查行 --> 檢查列 --> 檢查對角線 --> 檢查反對角線
輸出 棋局結果【1(X) is winner .】、【0(O) is winner .】、【平局 !】。

import java.util.Scanner;public class TicTacToe {public static void main(String[] args) {try {Scanner in = new Scanner(System.in);int [][] board = new int[3][3];for(int i = 0; i < board.length; i++) {//讀入for(int j = 0; j < board[i].length; j++) {board[i][j] = in.nextInt();}}int flag = -1; //-1: 平局; 1: (X)勝利; 0: (O)勝int num1 = 0; //1的數量 1代表Xint num0 = 0; //0的數量 0代表Ofor(int i = 0; i < board.length; i++) { //檢查行if(flag == -1) { //平局 --> 繼續驗證for(int j = 0; j < board[i].length; j++) {if(board[i][j] == 1) {num1++;} else {num0++;}}if(num1 == 3 || num0 == 3) {if(num1 == 3) {flag = 1;System.out.println("1(X) is winner .");break;} else {flag = 0;System.out.println("0(O) is winner .");break;}} else {flag = -1;break;}}}if(flag == -1) { //檢查列: 平局 --> 繼續驗證num1 = 0;num0 = 0;for(int i = 0; i < 3; i++) {if(flag == -1) {for(int j = 0; j < 3; j++) {if(board[j][i] == 1) {num1++;} else {num0++;}}if(num1 == 3 || num0 == 3) {if(num1 == 3) {flag = 1;System.out.println("1(X) is winner .");break;} else {flag = 0;System.out.println("0(O) is winner .");break;}} else {flag = -1;break;}}}}if(flag == -1) { //檢查對角線: 平局 --> 繼續驗證num1 = 0;num0 = 0;for(int i = 0; i < 3; i++) {if(board[i][i] == 1) {num1++;} else {num0++;}}if(num1 == 3 || num0 == 3) {if(num1 == 3) {flag = 1;System.out.println("1(X) is winner .");} else {flag = 0;System.out.println("0(O) is winner .");}} else {flag = -1;}}if(flag == -1) { //檢查反對角線: 平局 --> 繼續驗證num1 = 0;num0 = 0;for(int i = 0; i < 3; i++) {if(board[i][2-i] == 1) {num1++;} else {num0++;}}if(num1 == 3 || num0 == 3) {if(num1 == 3) {flag = 1;System.out.println("1(X) is winner .");} else {flag = 0;System.out.println("0(O) is winner .");}} else {flag = -1;}}if(flag == -1) {System.out.println("平局 !");}} catch(Exception e){System.out.println("程序異常 !");}} } /**檢查行: 1 1 1 0 1 0 0 0 1 1(X) is winner .0 0 0 1 0 0 0 0 1 0(O) is winner .平局: 0 1 0 0 1 1 1 0 1檢查對角線: 1 0 0 0 1 0 0 0 1 1(X)勝利:try {} catch(Exception e){} */

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