Description
Bash has set out on a journey to become the greatest Pokemon master. To get his first Pokemon, he went to Professor Zulu’s Lab. Since Bash is Professor Zulu’s favourite student, Zulu allows him to take as many Pokemon from his lab as he pleases.

But Zulu warns him that a group of k?>?1 Pokemon with strengths {s1,?s2,?s3,?…,?sk} tend to fight among each other if gcd(s1,?s2,?s3,?…,?sk)?=?1 (see notes for gcd definition).

Bash, being smart, does not want his Pokemon to fight among each other. However, he also wants to maximize the number of Pokemon he takes from the lab. Can you help Bash find out the maximum number of Pokemon he can take?

Note: A Pokemon cannot fight with itself.

Input
The input consists of two lines.

The first line contains an integer n (1?≤?n?≤?105), the number of Pokemon in the lab.

The next line contains n space separated integers, where the i-th of them denotes si (1?≤?si?≤?105), the strength of the i-th Pokemon.

Output
Print single integer — the maximum number of Pokemons Bash can take.

Examples
Input
3
2 3 4
Output
2
Input
5
2 3 4 6 7
Output
3
Note
gcd (greatest common divisor) of positive integers set {a1,?a2,?…,?an} is the maximum positive integer that divides all the integers {a1,?a2,?…,?an}.

In the first sample, we can take Pokemons with strengths {2,?4} since gcd(2,?4)?=?2.

In the second sample, we can take Pokemons with strengths {2,?4,?6}, and there is no larger group with gcd?≠?1.

#include <stdio.h> #include <stdlib.h>/* run this program using the console pauser or add your own getch, system("pause") or input loop */ int a[100010],ma[100010]; int main(int argc, char *argv[]) {int n;scanf("%d",&n);int i,j;for(i=0;i<n;i++){scanf("%d",&a[i]);for(j = 1 ; j * j <= a[i] ; j++)if(a[i] % j == 0){ma[j]++;if(j * j != a[i])ma[a[i] / j]++;}}int cut = 1;for(i = 2 ; i < 100001; i++){if(cut<ma[i])cut=ma[i];}printf("%d\n",cut);return 0; }

總結

以上是生活随笔為你收集整理的Bash's Big Day的全部內容，希望文章能夠幫你解決所遇到的問題。

如果覺得生活随笔網站內容還不錯，歡迎將生活随笔推薦給好友。