https://pan.baidu.com/s/1kVssDb5

TIPS：

提取密碼：assm

1.xor

2.hex2binary

3.len(bin(miwen))==len(bin(mingwen))

題解：?

工具：010Editor

使用010Editor打開兩個(gè)文件 , 轉(zhuǎn)換成二進(jìn)制模式

明文：

01101100 01101111 01110110 01100101 01101100 01101111 01110110 01100101 01101100 01101111 01110110 01100101 01101100 01101111 01110110 01100101 01101100 01101111 01110110 01100101 01101100 01101111 01110110 01100101 01101100 01101111 01110110 01100101 01101100 01101111 01110110 01100101

密文：

00001010 00000011 00010111 00000010 01010110 00000001 00010101 00010001 00001010 00010100 00001110 00001010 00011110 00110000 00001110 00001010 00011110 00110000 00001110 00001010 00011110 00110000 00010100 00001100 00011001 00001101 00011111 00010000 00001110 00000110 00000011 00011000

XOR處理

01100110 01101100 01100001 01100111 00111010 01101110 01100011 01110100 01100110 01111011 01111000 01101111 01110010 01011111 01111000 01101111 01110010 01011111 01111000 01101111 01110010 01011111 01100010 01101001 01110101 01100010 01101001 01110101 01100010 01101001 01110101 01111101

XOR處理源程序

C++版本

int main(){char a[] = "0000101000000011000101110000001001010110000000010001010100010001000010100001010000001110000010100001111000110000000011100000101000011110001100000000111000001010000111100011000000010100000011000001100100001101000111110001000000001110000001100000001100011000";char b[] = "0110110001101111011101100110010101101100011011110111011001100101011011000110111101110110011001010110110001101111011101100110010101101100011011110111011001100101011011000110111101110110011001010110110001101111011101100110010101101100011011110111011001100101";for(int i=0;i<256;i++){printf("%d",a[i]^b[i]);} }

Python版本

a = '0000101000000011000101110000001001010110000000010001010100010001000010100001010000001110000010100001111000110000000011100000101000011110001100000000111000001010000111100011000000010100000011000001100100001101000111110001000000001110000001100000001100011000' b = '0110110001101111011101100110010101101100011011110111011001100101011011000110111101110110011001010110110001101111011101100110010101101100011011110111011001100101011011000110111101110110011001010110110001101111011101100110010101101100011011110111011001100101' for i in range(len(a)):if(a[i] == b[i]):print '0',else:print '1',

打開010Editor , 創(chuàng)建一個(gè)新的Hex文件 , 粘貼為二進(jìn)制數(shù)據(jù)?

flag?

flag:nctf{xor_xor_xor_biubiubiu}?

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