今天有人在群里問到Python怎么把小寫數字轉換成中文的大寫字符，覺得這個問題很有趣，于是想了一下，就開始寫代碼了。

以下是代碼，感覺不足的地方就是如果是1001元，那么就會轉換成 壹仟零佰零拾壹圓，多了個零。這個代碼python2和python3都可以運行。

# -*- coding:utf-8 -*-

# date: 2018-02-28 11:48

def digital_to_chinese(digital):

str_digital = str(digital)

chinese = {"1": "壹", "2": "貳", "3": "叁", "4": "肆", "5": "伍", "6": "陸", "7": "柒", "8": "捌", "9": "玖", "0": "零"}

chinese2 = ["拾", "佰", "仟", "萬", "厘", "分", "角"]

jiao = ""

bs = str_digital.split(".")

yuan = bs[0]

if len(bs) > 1:

jiao = bs[1]

r_yuan = [i for i in reversed(yuan)]

count = 0

for i in range(len(yuan)):

if i == 0:

r_yuan[i] += "圓"

continue

r_yuan[i] += chinese2[count]

count += 1

if count == 4:

count = 0

chinese2[3] = "億"

s_jiao = [i for i in jiao][:3] # 去掉小于厘之后的

j_count = -1

for i in range(len(s_jiao)):

s_jiao[i] += chinese2[j_count]

j_count -= 1

last = [i for i in reversed(r_yuan)] + s_jiao

last_str = "".join(last)

print(str_digital)

print(last_str)

last_str = last_str.replace("0百", "0").replace("0十", "0").replace("000", "0").replace("00", "0").replace("0圓", "圓")

for i in range(len(last_str)):

digital = last_str[i]

if digital in chinese:

last_str = last_str.replace(digital, chinese[digital])

print(last_str)

return last_str

if __name__ == "__main__":

digital_to_chinese(123456789.456)

這是輸出

123456789.456

1億2仟3佰4拾5萬6仟7佰8拾9圓4角5分6厘

壹億貳仟叁佰肆拾伍萬陸仟柒佰捌拾玖圓肆角伍分陸厘

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