您可以使用這種方法來做到這一點,在此替換掉每一個？在查詢中使用(.*),然后根據(jù)它創(chuàng)建一個模式.然后應用另一對具有實際值的字符串,然后打印出將按？動態(tài)創(chuàng)建的所有組中的值.存在于查詢字符串中.

這是執(zhí)行相同操作的Java代碼.

@H_403_6@// This map stores your paired queries where key stores the placeholder query and value stores the query having actual parameters.

Map pairMap = new HashMap<>();

pairMap.put("SELECT * FROM my_table t WHERE (t.attr1 = ? AND t.attr2 = ?) OR t.attr3= ?","SELECT * FROM my_table t WHERE (t.attr1 = 3 AND t.attr2 = 'str') OR t.attr3= 4");

pairMap.put("UPDATE my_table SET attr2 = ? WHERE attr5 = ?","UPDATE my_table SET attr2 = 'Is it true?' WHERE attr5 = 'What is it?'");

pairMap.forEach((k,v) -> {

System.out.println("For query: "+k);

k = k.replaceAll("([*+^$()\\[\\]{}])","\\\\$1"); // this escapes all the characters that have special meaning in regex so they get treated as literal characters

k = k.replaceAll("\\?","(.*)");

Pattern p = Pattern.compile(k);

Matcher m = p.matcher(v);

if (m.matches()) {

for (int i=0;i

System.out.println(m.group(i+1));

}

} else {

System.out.println("Didn't match");

}

System.out.println();

});

哪個打印,

@H_403_6@For query: SELECT * FROM my_table t WHERE (t.attr1 = ? AND t.attr2 = ?) OR t.attr3= ?

3

'str'

4

For query: UPDATE my_table SET attr2 = ? WHERE attr5 = ?

'Is it true?'

'What is it?'

如您所見,該代碼適用于占位符？的任何可變值.在查詢字符串中,并打印配對查詢中存在的所有具有實際值的值.

總結

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