您可以使用除法和mod進(jìn)行所有這些操作。

long l1 = start.getTime();

long l2 = stop.getTime();

long diff = l2 - l1;

long secondInMillis = 1000;

long minuteInMillis = secondInMillis * 60;

long hourInMillis = minuteInMillis * 60;

long dayInMillis = hourInMillis * 24;

long elapsedDays = diff / dayInMillis;

diff = diff % dayInMillis;

long elapsedHours = diff / hourInMillis;

diff = diff % hourInMillis;

long elapsedMinutes = diff / minuteInMillis;

diff = diff % minuteInMillis;

long elapsedSeconds = diff / secondInMillis;

那應(yīng)該給您您要求的所有信息。

編輯：由于人們似乎很困惑，不，這不會(huì)考慮leap年或夏令時(shí)切換等問(wèn)題。這是純粹的消逝時(shí)間，這就是打開(kāi)要求的時(shí)間。

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