這個的修改直接是對于塊開一個數組，記錄修改的值就好了，，，（像不像標記永久化？？（2333，不知道從哪里掏出來的詞））

都是很樸素的分塊

1 #include<bits/stdc++.h> 2 #define N 1000005 3 #define LL long long 4 #define inf 0x3f3f3f3f 5 using namespace std; 6 inline int ra() 7 { 8 int x=0,f=1; char ch=getchar(); 9 while (ch<'0' || ch>'9') {if (ch=='-') f=-1; ch=getchar();} 10 while (ch>='0' && ch<='9') {x=x*10+ch-'0'; ch=getchar();} 11 return x*f; 12 } 13 int block,m,n,Q; 14 int add[N],sot[N],a[N],pos[N]; 15 int find(int i, int w) 16 { 17 int l=(i-1)*block+1,r=min(i*block,n),orz=r; 18 // for (int j=l; j<=r; j++) printf("%d ",sot[j]+add[i]); 19 if (l==r) return sot[l]+add[i]>=w; 20 while (l<r) 21 { 22 int mid=l+r>>1; 23 if (add[i]+sot[mid]>=w) r=mid; 24 else l=mid+1; 25 } 26 if (l==orz) return (sot[l]+add[i]>=w); 27 else return orz-l+1; 28 } 29 int ask(int l, int r, int w) 30 { 31 int ans=0; 32 if (pos[l]==pos[r]){ 33 for (int i=l; i<=r; i++) 34 if (add[pos[l]]+a[i]>=w) ans++; 35 } 36 else{ 37 for (int i=l; i<=pos[l]*block; i++) if (add[pos[l]]+a[i]>=w) ans++; 38 for (int i=(pos[r]-1)*block+1; i<=r; i++) if (add[pos[r]]+a[i]>=w) ans++; 39 // cout<<ans; 40 for (int i=pos[l]+1; i<pos[r]; i++) 41 ans+=find(i,w); 42 } 43 return ans; 44 } 45 void change(int l, int r, int w) 46 { 47 if (pos[l]==pos[r]){ 48 for (int i=l; i<=r; i++) a[i]+=w; 49 for (int i=(pos[l]-1)*block+1; i<=pos[l]*block; i++) 50 sot[i]=a[i]; 51 sort(sot+(pos[l]-1)*block+1,sot+pos[l]*block+1); 52 } 53 else { 54 for (int i=l; i<=pos[l]*block; i++) a[i]+=w; 55 for (int i=(pos[l]-1)*block+1; i<=pos[l]*block; i++) sot[i]=a[i]; 56 sort(sot+(pos[l]-1)*block+1,sot+pos[l]*block+1); 57 for (int i=(pos[r]-1)*block+1; i<=r; i++) a[i]+=w; 58 for (int i=(pos[r]-1)*block+1; i<=pos[r]*block; i++) sot[i]=a[i]; 59 sort(sot+(pos[r]-1)*block+1,sot+pos[r]*block+1); 60 for (int i=pos[l]+1; i<pos[r]; i++) add[i]+=w; 61 } 62 } 63 int main() 64 { 65 n=ra(); Q=ra(); 66 block=sqrt(n); m=n/block+(n%block!=0); 67 for (int i=1; i<=n; i++) 68 a[i]=ra(),pos[i]=(i-1)/block+1,sot[i]=a[i]; 69 for (int i=1; i<=m; i++) 70 { 71 int l=(i-1)*block+1,r=min(n,i*block); 72 sort(sot+l,sot+r+1); 73 } 74 while (Q--) 75 { 76 char s[3]; scanf("%s",s); int x=ra(),y=ra(),w=ra(); 77 if (s[0]=='M') change(x,y,w); 78 else printf("%d\n",ask(x,y,w)); 79 // for (int i=1; i<=n; i++) printf("%d ",a[i]+add[pos[i]]); cout<<endl; 80 } 81 return 0; 82 }

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轉載于:https://www.cnblogs.com/ccd2333/p/6435555.html

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