SQL查询重复记录方法大全 转
原文發布時間為:2010-08-09 —— 來源于本人的百度文章 [由搬家工具導入]
查找所有重復標題的記錄:
SELECT *
FROM t_info a
WHERE ((SELECT COUNT(*)
FROM t_info
WHERE Title = a.Title) > 1)
ORDER BY Title DESC
一。查找重復記錄
1。查找全部重復記錄
Select * From 表 Where 重復字段 In (Select 重復字段 From 表 Group By 重復字段 Having Count(*)>1)
2。過濾重復記錄(只顯示一條)
Select * From HZT Where ID In (Select Max(ID) From HZT Group By Title)
注:此處顯示ID最大一條記錄
二。刪除重復記錄
1。刪除全部重復記錄(慎用)
Delete FROM 表 Where 重復字段 In (Select 重復字段 From 表 Group By 重復字段 Having Count(*)>1)
2。保留一條(這個應該是大多數人所需要的 ^_^)
Delete FROM HZT Where ID Not In (Select Max(ID) From HZT Group By Title)
注:此處保留ID最大一條記錄
1、查找表中多余的重復記錄,重復記錄是根據單個字段(peopleId)來判斷
select * from people
where peopleId in (select?? peopleId from?? people group by?? peopleId having count(peopleId) > 1)
2、刪除表中多余的重復記錄,重復記錄是根據單個字段(peopleId)來判斷,只留有rowid最小的記錄
delete from people
where peopleId in (select?? peopleId from people group by?? peopleId?? having count(peopleId) > 1)
and rowid not in (select min(rowid) from?? people group by peopleId having count(peopleId )>1)
3、查找表中多余的重復記錄(多個字段)
select * from vitae a
where (a.peopleId,a.seq) in?? (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
4、刪除表中多余的重復記錄(多個字段),只留有rowid最小的記錄
delete from vitae a
where (a.peopleId,a.seq) in?? (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
5、查找表中多余的重復記錄(多個字段),不包含rowid最小的記錄
select * from vitae a
where (a.peopleId,a.seq) in?? (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
補充:
有兩個以上的重復記錄,一是完全重復的記錄,也即所有字段均重復的記錄,二是部分關鍵字段重復的記錄,比如Name字段重復,而其他字段不一定重復或都重復可以忽略。
1、對于第一種重復,比較容易解決,使用
select distinct * from tableName
就可以得到無重復記錄的結果集。
如果該表需要刪除重復的記錄(重復記錄保留1條),可以按以下方法刪除
select distinct * into #Tmp from tableName
drop table tableName
select * into tableName from #Tmp
drop table #Tmp
發生這種重復的原因是表設計不周產生的,增加唯一索引列即可解決。
2、這類重復問題通常要求保留重復記錄中的第一條記錄,操作方法如下
假設有重復的字段為Name,Address,要求得到這兩個字段唯一的結果集
select identity(int,1,1) as autoID, * into #Tmp from tableName
select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID
select * from #Tmp where autoID in(select autoID from #tmp2)
最后一個select即得到了Name,Address不重復的結果集(但多了一個autoID字段,實際寫時可以寫在select子句中省去此列)
轉載于:https://www.cnblogs.com/handboy/p/7163934.html
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