java计算时间跨度_请问如何使用Java计算时间跨度并格式化输出？
是的，Yup喚醒了我的死人，但這是基于@mtim發(fā)布的代碼的我改進的實現(xiàn)，因為該線程幾乎位于搜索的頂部，所以我弄得昏昏欲睡，
public static String getFriendlyTime(Date dateTime) {
StringBuffer sb = new StringBuffer();
Date current = Calendar.getInstance().getTime();
long diffInSeconds = (current.getTime() - dateTime.getTime()) / 1000;
/*long diff[] = new long[]{0, 0, 0, 0};
/* sec *? diff[3] = (diffInSeconds >= 60 ? diffInSeconds % 60 : diffInSeconds);
/* min *? diff[2] = (diffInSeconds = (diffInSeconds / 60)) >= 60 ? diffInSeconds % 60 : diffInSeconds;
/* hours *? diff[1] = (diffInSeconds = (diffInSeconds / 60)) >= 24 ? diffInSeconds % 24 : diffInSeconds;
/* days * diff[0] = (diffInSeconds = (diffInSeconds / 24));
*/
long sec = (diffInSeconds >= 60 ? diffInSeconds % 60 : diffInSeconds);
long min = (diffInSeconds = (diffInSeconds / 60)) >= 60 ? diffInSeconds % 60 : diffInSeconds;
long hrs = (diffInSeconds = (diffInSeconds / 60)) >= 24 ? diffInSeconds % 24 : diffInSeconds;
long days = (diffInSeconds = (diffInSeconds / 24)) >= 30 ? diffInSeconds % 30 : diffInSeconds;
long months = (diffInSeconds = (diffInSeconds / 30)) >= 12 ? diffInSeconds % 12 : diffInSeconds;
long years = (diffInSeconds = (diffInSeconds / 12));
if (years > 0) {
if (years == 1) {
sb.append("a year");
} else {
sb.append(years + " years");
}
if (years <= 6 && months > 0) {
if (months == 1) {
sb.append(" and a month");
} else {
sb.append(" and " + months + " months");
}
}
} else if (months > 0) {
if (months == 1) {
sb.append("a month");
} else {
sb.append(months + " months");
}
if (months <= 6 && days > 0) {
if (days == 1) {
sb.append(" and a day");
} else {
sb.append(" and " + days + " days");
}
}
} else if (days > 0) {
if (days == 1) {
sb.append("a day");
} else {
sb.append(days + " days");
}
if (days <= 3 && hrs > 0) {
if (hrs == 1) {
sb.append(" and an hour");
} else {
sb.append(" and " + hrs + " hours");
}
}
} else if (hrs > 0) {
if (hrs == 1) {
sb.append("an hour");
} else {
sb.append(hrs + " hours");
}
if (min > 1) {
sb.append(" and " + min + " minutes");
}
} else if (min > 0) {
if (min == 1) {
sb.append("a minute");
} else {
sb.append(min + " minutes");
}
if (sec > 1) {
sb.append(" and " + sec + " seconds");
}
} else {
if (sec <= 1) {
sb.append("about a second");
} else {
sb.append("about " + sec + " seconds");
}
}
sb.append(" ago");
/*String result = new String(String.format(
"%d day%s, %d hour%s, %d minute%s, %d second%s ago",
diff[0],
diff[0] > 1 ? "s" : "",
diff[1],
diff[1] > 1 ? "s" : "",
diff[2],
diff[2] > 1 ? "s" : "",
diff[3],
diff[3] > 1 ? "s" : ""));*/
return sb.toString();
}
顯然可以改進。基本上，它試圖使時間跨度更友好，但是有一些限制，即，如果經(jīng)過的時間(參數(shù))是將來的話，它的行為會很奇怪，并且僅限于天，小時和秒(不包括月和年)處理，以便其他人可以;-)。
示例輸出為：
大約一秒鐘前
8分34秒前
一個小時四分鐘前
一天前
29天前
一年零三個月前
，歡呼聲：D
編輯：現(xiàn)在支持月份和年份：P
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