位運算使奇數+1 偶數-1

Problem: Take input from the user (N) and print all EVEN and ODD numbers between 1 to N.

問題：從用戶那里輸入(N)，并打印1至N之間的所有偶數和奇數編號。

Solution:

解：

• Input an integer number (N).

  輸入一個整數( N )。

• Run two separate loops from 1 to N.

  從1到N運行兩個單獨的循環。

• In the first loop, check the condition to check EVEN numbers and print them.

  在第一個循環中，檢查條件以檢查偶數并打印它們。

• In the second loop, check the condition to check ODD numbers and print them.

  在第二個循環中，檢查條件以檢查奇數編號并打印它們。

• To check EVEN/ODD number – find the remainder dividing by 2, if it is 0 then the number will be an EVEN number, else the number will be an ODD number.

  要檢查EVEN / ODD號碼-找到除以2的余數，如果為0，則該號碼將為EVEN號碼，否則該號碼將為ODD號碼。

C++ program:

C ++程序：

// C++ program to print all // Even and Odd numbers from 1 to N#include <iostream> using namespace std;// function : evenNumbers // description: to print EVEN numbers only. void evenNumbers(int n) {int i;for (i = 1; i <= n; i++) {//condition to check EVEN numbersif (i % 2 == 0)cout << i << " ";}cout << "\n"; }// function : oddNumbers // description: to print ODD numbers only. void oddNumbers(int n) {int i;for (i = 1; i <= n; i++) {//condition to check ODD numbersif (i % 2 != 0)cout << i << " ";}cout << "\n"; }// main code int main() {int N;// input the value of Ncout << "Enter the value of N (limit): ";cin >> N;cout << "EVEN numbers are...\n";evenNumbers(N);cout << "ODD numbers are...\n";oddNumbers(N);return 0; }

Output

輸出量

RUN 1: Enter the value of N (limit): 11 EVEN numbers are... 2 4 6 8 10 ODD numbers are... 1 3 5 7 9 11RUN 2: Enter the value of N (limit): 50 EVEN numbers are... 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 50 ODD numbers are... 1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49

翻譯自: https://www.includehelp.com/cpp-programs/print-all-even-and-odd-numbers-from-1-to-n.aspx

位運算使奇數+1 偶數-1

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