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java bitset_Java BitSet intersects()方法与示例

發(fā)布時間:2025/3/11 java 16 豆豆
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java bitset

BitSet類intersects()方法 (BitSet Class intersects() method)

  • intersects() method is available in java.util package.

    intersects()方法在java.util包中可用。

  • intersects() method is used to check the common number of bits set to true in both the BitSet [this BitSet and the given BitSet(bs)].

    intersects()方法用于檢查BitSet [this BitSet和給定的BitSet(bs)]中設(shè)置為true的通用位數(shù)。

  • intersects() method is a non-static method, so it is accessible with the class object and if we try to access the method with the class name then we will get an error.

    intersects()方法是一種非靜態(tài)方法,因此可以通過類對象進行訪問,如果嘗試使用類名稱訪問該方法,則會收到錯誤消息。

  • intersects() method does not throw an exception at the time of checking the common number of bits set to true in both the BitSet.

    在檢查兩個BitSet中都設(shè)置為true的通用位數(shù)時, intersects()方法不會引發(fā)異常。

Syntax:

句法:

public boolean intersects(BitSet bs);

Parameter(s):

參數(shù):

  • BitSet bs – represents the BitSet to intersect with this BitSet.

    BitSet bs –表示要與此BitSet相交的BitSet。

Return value:

返回值:

The return type of this method is boolean, it returns true when the given BitSet(bs) has bits set to true and the same bits set to true in this BitSet otherwise it returns false.

這種方法的返回類型是布爾值 ,當給定的位集合(BS)具有設(shè)置為true比特,并在此BitSet設(shè)置為true,相同比特否則返回假 ,則返回true。

Example:

例:

// Java program to demonstrate the example // of boolean intersects(BitSet bs) method of BitSet.import java.util.*;public class IntersectsOfBitSet {public static void main(String[] args) {// create an object of two BitSetBitSet bs1 = new BitSet(10);BitSet bs2 = new BitSet(10);// By using set() method is to set// the values in BitSet 1 bs1.set(10);bs1.set(20);bs1.set(30);bs1.set(40);bs1.set(50);// By using set() method is to set// the values in BitSet 2 bs2.set(60);bs2.set(70);bs2.set(50);bs2.set(40);bs2.set(30);// Display Bitset1 and BitSet2System.out.println("bs1: " + bs1);System.out.println("bs2: " + bs2);// By using intersects(BitSet) method is to check whether// both the bitset has some common bits or notboolean status = bs1.intersects(bs2);// Display statusSystem.out.println("bs1.intersects(bs2): " + status);} }

Output

輸出量

bs1: {10, 20, 30, 40, 50} bs2: {30, 40, 50, 60, 70} bs1.intersects(bs2): true

翻譯自: https://www.includehelp.com/java/bitset-intersects-method-with-example.aspx

java bitset

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