python中八進制

Syntax to convert octal value to an integer (decimal format),

將八進制值轉換為整數(十進制格式)的語法，

int(oct_value, 8)

Here,

這里，

• oct_value should contain the valid octal value

  oct_value應該包含有效的八進制值

• 8 is the base value of the octal number system

  8是八進制數的基值

Note: oct_value must contain only octal digits (0, 1, 2, 3 ,4 ,5 ,6, 7), if it contains other than these digits a "ValueError" will return.

注意 ： oct_value必須僅包含八進制數字(0、1、2、3、4、5、6、7)，如果它不包含這些數字，則將返回“ ValueError” 。

程序將給定的八進制值轉換為整數(十進制) (Program to convert given octal value to integer (decimal))

# function to convert given octal Value # to an integer (decimal number) def OctToDec(value):try:return int(value, 8)except ValueError:return "Invalid Octal Value"# Main code input1 = "1234567" input2 = "7001236" input3 = "1278"print(input1, "as decimal: ", OctToDec(input1)) print(input2, "as decimal: ", OctToDec(input2)) print(input3, "as decimal: ", OctToDec(input3))

Output

輸出量

1234567 as decimal: 342391 7001236 as decimal: 1835678 1278 as decimal: Invalid Octal Value

Now, we are going to implement the program – that will take input the number as an octal number and printing it in the decimal format.

現在，我們將實現該程序–將輸入的數字作為八進制數字并以十進制格式打印。

程序以八進制格式輸入數字 (Program to input a number in octal format)

# input number in octal format and # converting it into decimal formattry:num = int(input("Input octal value: "), 8)print("num (decimal format):", num)print("num (octal format):", oct(num)) except ValueError:print("Please input only octal value...")

Output

輸出量

RUN 1: Input octal value: 1234567 num (decimal format): 342391 num (octal format): 0o1234567RUN 2: Input octal value: 12700546 num (decimal format): 2851174 num (octal format): 0o12700546RUN 3: Input octal value: 12807 Please input only octal value...

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翻譯自: https://www.includehelp.com/python/input-a-number-in-octal-format.aspx

python中八進制

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