expm1

數學類靜態double expm1(double d) (Math Class static double expm1(double d))

• This method is available in java.lang package.

  此方法在java.lang包中可用。

• This method is used to return [ the exponential of the given number – 1] in the method or in other words it is used to calculate the ( e raised to the power of the given argument – 1).?

  此方法用于返回方法中的[給定數字的指數– 1]，或換句話說，它用于計算(e升至給定參數的冪– 1)。

• In this method, expm stands for exponentiation.?

  在此方法中，expm代表求冪。

• This is a static method so this method is accessible with the class name too.?

  這是一個靜態方法，因此也可以使用類名訪問此方法。

• The return type of this method is double that means it returns (The exponentiation of the given argument -1) and the argument and return value are of double type.?

  此方法的返回類型為double，表示它返回(給定參數-1的冪)，并且參數和返回值均為double類型。

• In this method we pass only one parameter as an argument in the method of Math class and the given parameter is the exponent to raise the power of e -1.?

  在此方法中，我們僅將一個參數作為參數傳遞給Math類的方法，并且給定參數是提高e -1冪的指數。

• This method does not throw any exception.

  此方法不會引發任何異常。

Syntax:

句法：

public static double expm1(double d){}

Parameter(s):

參數：

double d – A double value whose exponential to be found..

double d –一個要找到其指數的double值。

Note:

注意：

• If we pass "NaN" to the function, it returns the "NaN".

  如果我們將“ NaN”傳遞給函數，它將返回“ NaN”。

• If we pass positive infinity, it returns the positive infinity.

  如果我們傳遞正無窮大，它將返回正無窮大。

• If we pass negative infinity, it returns -1.0.

  如果傳遞負無窮大，則返回-1.0。

• If we pass zero (-0 or 0), it returns 0.0.

  如果傳遞零(-0或0)，則返回0.0。

Return value:

返回值：

The return type of this method is double, it returns the exponentiation of the given value.

此方法的返回類型為double ，它返回給定值的冪。

Java程序演示expm1(double d)方法的示例 (Java program to demonstrate example of expm1(double d) method)

// Java program to demonstrate the example of expm1(double d) // method of Math Classpublic class Expm1Method {public static void main(String[] args) {// Here we are declaring few variablesdouble d1 = 7.0 / 0.0;double d2 = -7.0 / 0.0;double d3 = 0.0;double d4 = -0.0;double d5 = 0.8;double d6 = 2;// Display previous value of d1,d2,d3, d4,d5 and d6 System.out.println(" Before implementing expm1() so the value of d1 is :" + d1);System.out.println(" Before implementing expm1() so the value of d2 is :" + d2);System.out.println(" Before implementing expm1() so the value of d3 is :" + d3);System.out.println(" Before implementing expm1() so the value of d4 is :" + d4);System.out.println(" Before implementing expm1() so the value of d5 is :" + d5);System.out.println(" Before implementing expm1() so the value of d6 is :" + d6);// Here , we will get (Infinity) because we are passing parameter // whose value is (infinity)System.out.println("After implementing expm1() so the value of d1 is :" + Math.expm1(d1));// Here , we will get (-1.0) because we are passing parameter // whose value is (-infinity)System.out.println("After implementing expm1() so the value of d2 is :" + Math.expm1(d2));// Here , we will get (0.0) because we are passing parameter // whose value is (0.0)System.out.println("After implementing expm1() so the value of d3 is :" + Math.expm1(d3));// Here , we will get (-0.0) because we are passing parameter // whose value is (-0.0)System.out.println("After implementing expm1() so the value of d4 is :" + Math.expm1(d4));// Here , we will get [(e raised to the power of 0.8) - 1] // because we are passing parameter whose value is (0.8)System.out.println("After implementing expm1() so the value of d5 is :" + Math.expm1(d5));// Here , we will get [(e raised to the power of 2) - 1] // because we are passing parameter whose value is (2)System.out.println("After implementing expm1() so the value of d6 is :" + Math.expm1(d6));} }

Output

輸出量

E:\Programs>javac Expm1Method.javaE:\Programs>java Expm1Method Before implementing expm1() so the value of d1 is :Infinity Before implementing expm1() so the value of d2 is :-Infinity Before implementing expm1() so the value of d3 is :0.0 Before implementing expm1() so the value of d4 is :-0.0 Before implementing expm1() so the value of d5 is :0.8 Before implementing expm1() so the value of d6 is :2.0After implementing expm1() so the value of d1 is :Infinity After implementing expm1() so the value of d2 is :-1.0 After implementing expm1() so the value of d3 is :0.0 After implementing expm1() so the value of d4 is :-0.0 After implementing expm1() so the value of d5 is :1.2255409284924677 After implementing expm1() so the value of d6 is :6.38905609893065

翻譯自: https://www.includehelp.com/java/math-class-static-double-expm1-double-d-with-example.aspx

expm1

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