手機子王掩碼和網關查找

Problem statement: Write a C program to find odd or even no using bitwise operators.

問題陳述：編寫一個C程序以使用按位運算符查找奇數或什至無 。

Solution: We can use bitwise operator here to solve the problem.

解決方案：我們可以在這里使用按位運算符來解決問題。

Solution

解

Let n be a numbern &1 = 0000000d where d is the LSB of n So, If LSB ==1It's odd numberElseEven no

To understand the concept of "LSB" & bitwise operators please read: Bitwise Operators and their working with Examples in C

要了解“ LSB”和按位運算符的概念，請閱讀： 按位運算符及其在C語言中與Example一起使用

Example:

例：

Let n be 7 //00000111n & 1 = 1 00000111(7) & 00000001(1) =00000001 (1)Thus it's an odd numberLet n be 6 //00000110N&1=000000110(6) & 00000001(1) =00000000 (0)Thus it's an even number

C implementation

C實現

#include <stdio.h>int main() {int n;printf("enter no: ");scanf("%d",&n);//n&1 actually results in 0000000d where d is your LSBif(n&1==1)printf("it's odd no");//for odd no LSB 1elseprintf("it's even no");//for even no LSB 0return 0; }

Output

輸出量

First run: enter no: 7 it's odd noSecond run: enter no: 6 it's even no

翻譯自: https://www.includehelp.com/c-programs/find-odd-or-even-number-using-bitmasking.aspx

手機子王掩碼和網關查找

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