現在看下強大的atof()函數，哇哈哈：

/* Convert a string to a double. */

double

atof (const char *nptr)

{

return strtod (nptr, (char **) NULL);

}

#if HAVE_CONFIG_H

# include

#endif

#include

#ifndef errno

extern int errno;

#endif

#include

#if defined (STDC_HEADERS) || (!defined (isascii) && !defined (HAVE_ISASCII))

# define IN_CTYPE_DOMAIN(c) 1

#else

# define IN_CTYPE_DOMAIN(c) isascii(c)

#endif

#define ISSPACE(c) (IN_CTYPE_DOMAIN (c) && isspace (c))

#define ISDIGIT(c) (IN_CTYPE_DOMAIN (c) && isdigit (c))

#define TOLOWER(c) (IN_CTYPE_DOMAIN (c) ? tolower(c) : (c))

#include

#include

#include

#include

/* Convert NPTR to a double. If ENDPTR is not NULL, a pointer to the

character after the last one used in the number is put in *ENDPTR. */

double

strtod (const char *nptr, char **endptr)

{

register const char *s;

short int sign;

/* The number so far. */

double num;

int got_dot; /* Found a decimal point. */

int got_digit; /* Seen any digits. */

/* The exponent of the number. */

long int exponent;

if (nptr == NULL) /*如果為空串,則結束轉換*/

{

errno = EINVAL;

goto noconv; /*轉向處理無法轉換的代碼*/

}

s = nptr;

/* Eat whitespace. */

while (ISSPACE (*s))

++s;

/* Get the sign. */

sign = *s == '-' ? -1 : 1;

if (*s == '-' || *s == '+')

++s;

num = 0.0;

got_dot = 0;

got_digit = 0;

exponent = 0;

for (;; ++s)

{

if (ISDIGIT (*s))

{

got_digit = 1;

/* Make sure that multiplication by 10 will not overflow. */

if (num > DBL_MAX * 0.1)

/* The value of the digit doesn't matter, since we have already

gotten as many digits as can be represented in a `double'.

This doesn't necessarily mean the result will overflow.

The exponent may reduce it to within range.

We just need to record that there was another

digit so that we can multiply by 10 later. */

++exponent;

else

num = (num * 10.0) + (*s - '0');

/* Keep track of the number of digits after the decimal point.

If we just divided by 10 here, we would lose precision. */

if (got_dot)

--exponent;

}

else if (!got_dot && *s == '.')

/* Record that we have found the decimal point. */

got_dot = 1;

else

/* Any other character terminates the number. */

break;

}

if (!got_digit)

goto noconv;

if (TOLOWER (*s) == 'e')

{

/* Get the exponent specified after the `e' or `E'. */

int save = errno;

char *end;

long int exp;

errno = 0;

++s;

exp = strtol (s, &end, 10);

if (errno == ERANGE)

{

/* The exponent overflowed a `long int'. It is probably a safe

assumption that an exponent that cannot be represented by

a `long int' exceeds the limits of a `double'. */

if (endptr != NULL)

*endptr = end;

if (exp < 0)

goto underflow;

else

goto overflow;

}

else if (end == s)

/* There was no exponent. Reset END to point to

the 'e' or 'E', so *ENDPTR will be set there. */

end = (char *) s - 1;

errno = save;

s = end;

exponent += exp;

}

if (endptr != NULL)

*endptr = (char *) s;

if (num == 0.0)

return 0.0;

/* Multiply NUM by 10 to the EXPONENT power,

checking for overflow and underflow. */

if (exponent < 0)

{

if (num < DBL_MIN * pow (10.0, (double) -exponent))

goto underflow;

}

else if (exponent > 0)

{

if (num > DBL_MAX * pow (10.0, (double) -exponent))

goto overflow;

}

num *= pow (10.0, (double) exponent);

return num * sign;

overflow:

/* Return an overflow error. */

errno = ERANGE;

return HUGE_VAL * sign;

underflow:

/* Return an underflow error. */

if (endptr != NULL)

*endptr = (char *) nptr;

errno = ERANGE;

return 0.0;

noconv:

/* There was no number. */

if (endptr != NULL)

*endptr = (char *) nptr;

return 0.0;

}

總結

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