下面的代碼片段可以幫助您完成最后一個任務。

如果在字符串的開始或結尾之外的其他地方發現了特殊字符，則對于子集的恢復沒有特殊處理。在# Special chars which should be ignored for reverting

SPECIALCHARS = [' ', '.', ',']

def reverse( string_ ):

# Find occurence of 'special' chars. Stack position and char into a list.

specchar = [( i, ltr ) for i, ltr in enumerate( string_ ) if ltr in SPECIALCHARS]

if specchar:

# Remove all the special characters

newstring = ''.join( c for c in string_ if c not in SPECIALCHARS )

# Reverse the legal characters

newstring = newstring[::-1]

offset = 0

# Re-insert the removed special chars

for pos, char in specchar:

if pos + 1 + offset >= len( newstring ):

# Append at the end

newstring += char

else:

# Insert

newstring = newstring[:pos + offset] + char + newstring[pos + offset:]

offset += 1

return newstring

else: # No special char at all, so just revert

return string_[::-1]

print " '%s' =?= ' riatsilA, '" % ( reverse( " Alistair, " ) )

將導致以下輸出：' riatsilA, ' =?= ' riatsilA, '

只需返回忽略第一個和最后一個字符是一行代碼。

用這個來反轉“中間”：t[1:-1][：：-1]

然后添加第一個和最后一個字符。在

^{pr2}$

編輯

好吧，現在我想我明白你想要什么了：-)newstr = ""

fullstr = ""

for char in mystr:

if char in SPECIALCHARS:

if len( newstr ): # Is already something to invert there?

#Ignore 1st and last char and revert the rest

newstr = newstr[0] + newstr[1:-1][::-1] + newstr[-1]

fullstr += newstr + char

else: # Special char found but nothing to revert so far

fullstr += char

newstr = ""

else: # No special char so just append

newstr += char

print "'%s'" % fullstr

總結

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