我想根據時間信息計算項目(0,1,2,3….)之間的相似性。時間信息可以是時間即時(startdate)、時間間隔(startdate、enddate)或null(NaT)；請參閱下面的dataframe(df_for)的示例。在

{instant，instant}：如果等于sim=1，則sim=0

{instant，null}或相反，sim=0

{instant，interval}：如果instant在interval內，sim=1，或者如果一個interval包含一個instant，sim=1

{interval，interval}：如果區間重疊，sim=兩個區間的交集/兩個區間的并集

{interval，interval}：如果一個間隔包含另一個，則sim=1

下面的python代碼從dataframe獲取時態信息，并執行上述條件(1-5)。代碼很冗長，我想知道是否有一種聰明的方法/lib來使用python計算時間段和時間瞬間之間的相似性。在m, k = df_for.shape

sim = np.zeros((m, m))

data = df_for.values

for i in range(m):

for j in range(m):

if i != j:

st1 = data[i][0]

ed1 = data[i][1]

st2 = data[j][0]

ed2 = data[j][1]

#both items are null values

if pd.isnull(st1) and pd.isnull(ed1) and pd.isnull(st2) and pd.isnull(ed2):

sim[i][j] = 0.

# {instant, instant} => equal, not equal

if pd.notnull(st1) and pd.isnull(ed1) and pd.notnull(st2) and pd.isnull(ed2):

if st1 == st2:

sim[i][j] = 1.

else:

sim[i][j] = 0.

# {instant, null} => sim is 0

if pd.notnull(st1) and pd.isnull(ed1) and pd.isnull(st2) and pd.isnull(ed2):

sim[i][j] = 0.

# {instant, interval} => meets, during

if pd.notnull(st1) and pd.isnull(ed1) and pd.notnull(st2) and pd.notnull(ed2):

if(st2 <= st1 <= ed2):

sim[i][j] = 1. #a time is between two other times

else:

sim[i][j] = 0.

# {interval, instant} => meets, contains

if pd.notnull(st1) and pd.notnull(ed1) and pd.notnull(st2) and pd.isnull(ed2):

if(st1 <= st2 <= ed1):

sim[i][j] = 1. #a time is between two other times

else:

sim[i][j] = 0.

# {interval, interval} => equal, overlaps, not overlaps

if pd.notnull(st1) and pd.notnull(ed1) and pd.notnull(st2) and pd.notnull(ed2):

if (st1 <= st2 <= ed1) or (st2 <= st1 <= ed2):

intersect = min(ed1,ed2)- max(st1,st2) # earliestend-lateststart

union = max(st1,st2,ed1,ed2) - min(ed1,ed2,st1,st2)

overlaps = intersect/union

#print(intersect/np.timedelta64(1, 'D'),union/np.timedelta64(1, 'D'))

if (st1 > st2 and ed1 < ed2) or (st1 < st2 and ed1 > ed2): # contains, during

overlaps = 1.0

sim[i][j]=overlaps

else:

sim[i][j] = 0.

else:

sim[i][j] = 1.

總結

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