[导入]通过简易的前台代码实现无限二级域名转向（来自无忧 biyuan老矣)
只要空間支持泛域名解析，無須服務端腳本語言和DNS，通過前臺代碼便可實現無限二級域名的構造：
<html>???
<head>???
<title>碧原網絡免費二級域名</title>???
<head>???
</head>???
<body>???
<scrīpt language="Javascrīpt">???
<!--???
//全局變量???
var cUrl = "http://www2.17389.com/"????????????????//當處理失敗時跳轉的站點或目錄???
var Url = "17389";????????????????????????//頂級域名的關鍵字，這里是www.17389.com???
var sUrl = location.href;????????????????????//獲取當前用戶輸入地址???
var oUrl = ((sUrl.split(".")[0]).split("//")[1]);????????//對用戶獲取的地址進行分割???
var xUrl = false;????????????????????????//創建一個全局變量，方便判斷記錄集是否存在???
??
//用戶信息???
var User = new Array();???
User[0] = new Array("biyuan","http://aoao.52ui.com/biyuan/","碧原在線");????
User[1] = new Array("fhonline","http://www.17389.com","飛鴻網絡");????
User[2] = new Array("51js","http://www.51js.com/","無憂腳本");????
User[3] = new Array("ucren","http://www.ucren.com/","游戲人");????
User[4] = new Array("aoao","http://aoao.52ui.com/","無憂嗷嗷");????
??
//判斷頂級域名合法性???
if (sUrl.split(".")[1] != Url){???
????????location.href = cUrl;???
}???
??
//匹配數據，執行跳轉???
else {???
????????for (var j=0;j < User.length;j++){???
????????????????if (oUrl == User[j][0]){???
????????????????????????document.write ("正在加載" + User[j][2] + ",請稍候....");????//跳轉時顯示的信息???
????????????????????????document.title = User[j][2];????????????????????//跳轉時標題欄的信息???
????????????????????????xUrl = User[j][1];????????????????????????//對全局變量進行賦值???
????????????????????????setTimeout("location.href = xUrl",5000);????????????//停留5秒后執行跳轉???
????????????????}???
????????}???
}???
??
//記錄不存在提示錯誤信息???
if(!xUrl){???
????????document.write("找不到該域名.停留10秒以后跳轉到<a href='" + cUrl + "'>碧原網絡</a>");???
????????setTimeout("location.href = cUrl",10000);???
}???
??
//-->???
</scrīpt>???
</body>???
</html>?
suiqirui 2007-05-15 23:31 發表評論
文章來源:http://www.cnblogs.com/suiqirui19872005/archive/2007/05/15/747805.html
轉載于:https://www.cnblogs.com/QiRuiNet-helloworld/archive/2007/06/17/786343.html
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