傻瓜
Description
判斷一個(gè)數(shù)是否為素?cái)?shù)
Input
一個(gè)數(shù)n(2<n<100)
Output
該數(shù)如果是素?cái)?shù),則輸出Yes,否則輸出No
Sample Input
2
Sample Output
Yes
- #include <iostream> using namespace std; int main() {int n,i,bz;cin>>n;bz=0;for (i=2;i<=n-1;i++)if (n%i==0){cout<<"No"<<endl;bz=1;break;}if (bz==0) cout<<"Yes"<<endl; return 0; }
轉(zhuǎn)載于:https://www.cnblogs.com/YYC-0304/p/9500128.html
總結(jié)