我有一個(gè)Python代碼應(yīng)用程序,它記錄鼠標(biāo)活動(dòng)(按規(guī)則間隔記錄的點(diǎn),時(shí)間等待),然后處理數(shù)據(jù)以輸出鼠標(biāo)移動(dòng)的角度(Y軸為0)和它移動(dòng)的速度。

目前我的輸出是東0度,南-90度,西180度,北90度,這不是我的預(yù)期輸出。我不確定三角法或其他計(jì)算中是否有問(wèn)題,所以希望對(duì)這方面的任何幫助。

i = 0

angles = []

speeds = []

#positions is an array of coordinates taken 0.1 seconds apart from each other

for point in positions:

if i is not 0:

pointY = 2500 - point[1] #invert position of X and assign variable

deltaX = point[0]-pointXP # difference is current pointX minus PointXPast

deltaY = pointY-pointYP

dist = math.sqrt(deltaX**2 + deltaY**2) #distance is the hypotenuse

if dist is 0: #if the mouse has not moved

continue

speed = dist/timeWait # speed is distance/time

angle = math.degrees(math.atan2(deltaY,deltaX)) #angle using Tan

angles.append(angle)

speeds.append(speed)

pointXP = point[0]

pointYP = pointY

else: #this is only for the first iteration

i = 1

pointXP = point[0]

pointYP = 2500 - point[1]

continue

再次感謝您的幫助,特別是關(guān)于我的角度被關(guān)閉。謝謝。

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