1 #!/usr/bin/env python 2 # -*- coding:UTF-8 -*- 3 4 import crypt 5 import sys 6 7 # 哈希密碼的前兩位就是鹽的前兩位，這里我們假設(shè)鹽只有兩位。 8 # 程序分兩部分，一部分是打開字典，另一部分是哈希匹配密碼 9 10 #standard DES, two salt 11 def desPass(cryptpass): 12 #get salt from the front place 13 saltf = cryptpass[0:2] 14 return saltf 15 16 #for $6$ 17 def sha512Pass(cryptpass): 18 saltf = "$6$"+cryptpass.split("$")[2] 19 return saltf 20 21 #for $5$ 22 def sha256Pass(cryptpass): 23 saltf = "$5$"+cryptpass.split("$")[2] 24 # saltf = "$5$rounds=5000$anexamplestringf" 25 return saltf 26 27 def main(): 28 banner = ''' 29 python CrackPass.py 5 30 one params is type for you are cracking 31 0 ---- standard DES for 2 salt 32 5 ---- sha256 crypt $5$salt$secret 33 6 ---- sha512 crypt $6$salt$secret 34 35 salt contains $5$salt 36 if $salt contain "$",will cause inaccuracy. Maybe you need set the salt by your hand,for example:# saltf = "$5$rounds=5000$anexamplestringf" 37 ''' 38 print banner 39 method = sys.argv[1] 40 passfile = open('Password','r') 41 #從文件中一行一行讀取 42 for line in passfile.readlines(): 43 cryptpass = line.strip() 44 print "Cracking Password For: %s"%cryptpass 45 46 #select type 47 if method == "0": 48 salt = desPass(cryptpass) 49 elif method == "6": 50 salt = sha512Pass(cryptpass) 51 elif method == "5": 52 salt = sha256Pass(cryptpass) 53 print salt 54 dictfile = open('dictionary','r') 55 for word in dictfile.readlines(): 56 word = word.strip('\n') 57 cryWord = crypt.crypt(word,salt) 58 59 if cryptpass == cryWord: 60 print "Found passwd: %s"%word 61 print "ok" 62 return 63 print "Password not found!" 64 65 if __name__ == '__main__': 66 main()

現(xiàn)在只寫了$6$　　$5$開頭的和一種普通的DES兩位鹽加密的

爆破linux一般用￥6￥

注意一般密文由3部分組成，以”$”分隔，第一部分為ID，第二部分為鹽值，第三部分為加密密文

真正的鹽值包括ID部分，我上面判斷salt是根據(jù)$分割，默認(rèn)是密文中只有三個(gè)$

有時(shí)salt中本來就含有$,

這時(shí)就需要自己指定salt了，saltf = "$5$rounds=5000$anexamplestringf"

可以觀察出來，觀察不出來，就多嘗試

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轉(zhuǎn)載于:https://www.cnblogs.com/kunspace/p/10583774.html

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