linux 批量替换文件内容及查找某目录下所有包含某字符串的文件(批量修改文件内容)
轉自 http://blog.csdn.net/werm520/article/details/49334513
grep -rl ‘10.100.137.5’ | xargs sed -i ‘10.100.146.239’
C代碼 收藏代碼
grep -rl matchstring somedir/ | xargs sed -i ‘s/string1/string2/g’
例如:
對象:文件夾
C代碼 收藏代碼
grep -rl ‘windows’ ./path | xargs sed -i ‘s/windows/linux/g’
find
對象:文件
C代碼 收藏代碼
find -name ‘test’ | xargs perl -pi -e ‘s|windows|linux|g’
這里使用了perl語言,使用-e加上一段代碼,從而批量地將當前目錄及所有子目錄下的file.log文件中的string1替換成了string2; string支持正則表達式
awk
C代碼 收藏代碼
grep -i “windows” -r ./path | awk -F : ‘{print $1}’ | sort | uniq | xargs sed -i ‘s/windows/linux/g’
這里使用了shell命令,先查找出文件,再用awk分割(以:切分),再行替換!
注意: grep可以使用正則,也可以使用\轉義一些特殊字符,比如“等
sed -i ‘s/\”localhost\”/\”10.2.2.2\”/g’ /home/my.conf
更多:
sed replace word / string syntax
The syntax is as follows:
C代碼 收藏代碼
sed -i ‘s/old-word/new-word/g’ *.txt
GNU sed command can edit files in place (makes backup if extension supplied) using the -i option. If you are using an old UNIX sed command version try the following syntax:
C代碼 收藏代碼
sed ‘s/old/new/g’ input.txt > output.txt
You can use old sed syntax along with bash for loop:
C代碼 收藏代碼
!/bin/bash
OLD=”xyz”
NEW=”abc”
DPATH=”/home/you/foo/*.txt”
BPATH=”/home/you/bakup/foo”
TFILE=”/tmp/out.tmp.$$”
[ ! -d $BPATH ] && mkdir -p $BPATH || :
for f in $DPATH
do
if [ -f $f -a -r $f ]; then
/bin/cp -f $f $BPATH
sed “s/$OLD/$NEW/g” “$f” > $TFILE && mv $TFILE “$f”
else
echo “Error: Cannot read $f”
fi
done
/bin/rm $TFILE
A Note About Bash Escape Character
A non-quoted backslash \ is the Bash escape character. It preserves the literal value of the next character that follows, with the exception of newline. If a \newline pair appears, and the backslash itself is not quoted, the \newline is treated as a line continuation (that is, it is removed from the input stream and effectively ignored). This is useful when you would like to deal with UNIX paths. In this example, the sed command is used to replace UNIX path “/nfs/apache/logs/rawlogs/access.log” with “DOMAIN_LOG_FILE“:
C代碼 收藏代碼
!/bin/bash
Our path
_r1=”/nfs/apache/logs/rawlogs/access.log”
Escape path for sed using bash find and replace
_r1=”${_r1//\//\/}”
replace DOMAIN_LOG_FILE in our sample.awstats.conf
sed -e “s/DOMAIN_LOG_FILE/${_r1}/” /nfs/conf/awstats/sample.awstats.conf > /nfs/apache/logs/awstats/awstats.conf
call awstats
/usr/bin/awstats -c /nfs/apache/logs/awstats/awstats.conf
The $_r1 is escaped using bash find and replace parameter substitution syntax to replace each occurrence of /with \/.
perl -pie Syntax For Find and Replace
The syntax is as follows:
C代碼 收藏代碼
perl -pie ‘s/old-word/new-word/g’ input.file > new.output.file
來源:http://www.cyberciti.biz/faq/unix-linux-replace-string-words-in-many-files/
linux下查找某目錄下所有文件包含某字符串的命令
C代碼 收藏代碼
從文件內容查找匹配指定字符串的行:
$ grep “被查找的字符串” 文件名
從文件內容查找與正則表達式匹配的行:
$ grep –e “正則表達式” 文件名
查找時不區分大小寫:
$ grep –i “被查找的字符串” 文件名
查找匹配的行數:
$ grep -c “被查找的字符串” 文件名
從文件內容查找不匹配指定字符串的行:
$ grep –v “被查找的字符串” 文件名
從根目錄開始查找所有擴展名為.txt的文本文件,并找出包含”linux”的行
find . -type f -name “*.txt” | xargs grep “linux”
總結
以上是生活随笔為你收集整理的linux 批量替换文件内容及查找某目录下所有包含某字符串的文件(批量修改文件内容)的全部內容,希望文章能夠幫你解決所遇到的問題。
- 上一篇: 路径知识
- 下一篇: Ubuntu 20.04 linux系统