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spring 的权限控制:security

發布時間:2025/3/18 编程问答 22 豆豆
生活随笔 收集整理的這篇文章主要介紹了 spring 的权限控制:security 小編覺得挺不錯的,現在分享給大家,幫大家做個參考.

下面我們將實現關于Spring Security3的一系列教程.?
最終的目標是整合Spring Security + Spring3MVC?
完成類似于SpringSide3中mini-web的功能.?

Spring Security是什么??

引用

Spring Security,這是一種基于Spring AOP和Servlet過濾器的安全框架。它提供全面的安全性解決方案,同時在Web請求級和方法調用級處理身份確認和授權。在Spring Framework基礎上,Spring Security充分利用了依賴注入(DI,Dependency Injection)和面向切面技術。



關于Spring Security學習的資料.?
最重要,最齊全的中文資料當然是family168的中文文檔?
Spring Security2參考文檔?

Spring Security3 參考文檔?

附件包含了一個很好的初入門的PDF教程.?
最好是花30分鐘先照著PDF上的教程一步一步的操作.?
雖然沒有實際的應用價值,但對初學者認識SpringSecurity3很有幫助.?

我們的項目目錄結構最終是:?

?


需要添加的jar包:?

?


我們先實現一個controller:?

MainController.java?

Java代碼??

  • package?org.liukai.tutorial.controller;??

  • ??

  • import?org.apache.log4j.Logger;??

  • import?org.springframework.stereotype.Controller;??

  • import?org.springframework.web.bind.annotation.RequestMapping;??

  • import?org.springframework.web.bind.annotation.RequestMethod;??

  • ??

  • @Controller??

  • @RequestMapping("/main")??

  • public?class?MainController?{??

  • ????protected?static?Logger?logger?=?Logger.getLogger("controller");??

  • ??

  • ????/**?

  • ?????*?跳轉到commonpage頁面?

  • ?????*??

  • ?????*?@return?

  • ?????*/??

  • ????@RequestMapping(value?=?"/common",?method?=?RequestMethod.GET)??

  • ????public?String?getCommonPage()?{??

  • ????????logger.debug("Received?request?to?show?common?page");??

  • ????????return?"commonpage";??

  • ????}??

  • ??

  • ????/**?

  • ?????*?跳轉到adminpage頁面?

  • ?????*??

  • ?????*?@return?

  • ?????*/??

  • ????@RequestMapping(value?=?"/admin",?method?=?RequestMethod.GET)??

  • ????public?String?getAadminPage()?{??

  • ????????logger.debug("Received?request?to?show?admin?page");??

  • ????????return?"adminpage";??

  • ??

  • ????}??

  • ??

  • }??



  • 該controller有兩個mapping映射:?

    引用

    main/common?
    main/admin



    現在我們將同過Spring Security3框架實現成功登陸的人都能訪問到main/common.?
    但只有擁有admin權限的用戶才能訪問main/admin.?


    我們先在web.xml中開啟Spring3MVC和SpringSecurity3.?

    web.xml?

    Xml代碼??

  • <?xml?version="1.0"?encoding="UTF-8"?>??

  • <web-app?id="WebApp_ID"?version="2.4"??

  • ????xmlns="http://java.sun.com/xml/ns/j2ee"???

  • ????xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"??

  • ????xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee???

  • ????http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">??

  • ??????

  • ????<!--?SpringSecurity必須的filter?-->??

  • ????<filter>??

  • ????????<filter-name>springSecurityFilterChain</filter-name>??

  • ????????<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>??

  • ????</filter>??

  • ??

  • ????<filter-mapping>??

  • ????????<filter-name>springSecurityFilterChain</filter-name>??

  • ????????<url-pattern>/*</url-pattern>??

  • ????</filter-mapping>??

  • ??

  • ????<context-param>??

  • ????????<param-name>contextConfigLocation</param-name>??

  • ????????<param-value>??

  • ????????/WEB-INF/spring-security.xml??

  • ????????/WEB-INF/applicationContext.xml??

  • ????????</param-value>??

  • ????</context-param>??

  • ??

  • ????<servlet>??

  • ????????<servlet-name>spring</servlet-name>??

  • ????????<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>??

  • ????????<load-on-startup>1</load-on-startup>??

  • ????</servlet>??

  • ??

  • ????<servlet-mapping>??

  • ????????<servlet-name>spring</servlet-name>??

  • ????????<url-pattern>/</url-pattern>??

  • ????</servlet-mapping>??

  • ??

  • ????<listener>??

  • ????????<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>??

  • ????</listener>??

  • ??

  • </web-app>??



  • 要啟用SpringSecurity3,我們需要完成以下兩步:?
    1.在web.xml中聲明DelegatingFilterProxy.?

    Xml代碼??

  • <filter-mapping>??

  • ????????<filter-name>springSecurityFilterChain</filter-name>??

  • ????????<url-pattern>/*</url-pattern>??

  • ????</filter-mapping>??



  • 表示項目中所有路徑的資源都要經過SpringSecurity.?

    2.導入指定的SpringSecurity配置 :spring-security.xml?

    關于spring-security.xml的配置.?
    我們把這個放到后面配置.以便更詳細的講解.?

    注意一點.最好是將DelegatingFilterProxy寫在DispatcherServlet之前.否則?
    SpringSecurity可能不會正常工作.
    ?


    在web.xml中我們定義servlet:spring.?
    按照慣例,我們必須聲明一個spring-servle.xml?
    spring-servle.xml?

    Xml代碼??

  • <?xml?version="1.0"?encoding="UTF-8"?>??

  • <beans?xmlns="http://www.springframework.org/schema/beans"??

  • ????xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"?xmlns:p="http://www.springframework.org/schema/p"??

  • ????xsi:schemaLocation="http://www.springframework.org/schema/beans???

  • ????????????http://www.springframework.org/schema/beans/spring-beans-3.0.xsd">??

  • ??

  • ????<!--?定義一個視圖解析器?-->??

  • ????<bean?id="viewResolver"??

  • ????????class="org.springframework.web.servlet.view.InternalResourceViewResolver"??

  • ????????p:prefix="/WEB-INF/jsp/"?p:suffix=".jsp"?/>??

  • ??

  • </beans>??



  • 這個XML配置聲明一個視圖解析器.在控制器中會根據JSP名映射到/ WEB-INF/jsp中相應的位置.?


    然后創建一個applicationContext.xml.?

    applicationContext.xml.?

    Xml代碼??

  • <?xml?version="1.0"?encoding="UTF-8"?>??

  • <beans?xmlns="http://www.springframework.org/schema/beans"??

  • ????xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"???

  • ????xmlns:context="http://www.springframework.org/schema/context"??

  • ????xmlns:mvc="http://www.springframework.org/schema/mvc"??

  • ????xsi:schemaLocation="http://www.springframework.org/schema/beans???

  • ????????????http://www.springframework.org/schema/beans/spring-beans-3.0.xsd??

  • ????????????http://www.springframework.org/schema/context??

  • ????????????http://www.springframework.org/schema/context/spring-context-3.0.xsd??

  • ????????????http://www.springframework.org/schema/mvc???

  • ????????????http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd">??

  • ??

  • ????<!--?激活spring的注解.?-->??

  • ????<context:annotation-config?/>??

  • ??

  • ????<!--?掃描注解組件并且自動的注入spring?beans中.???

  • ????例如,他會掃描@Controller?和@Service下的文件.所以確保此base-package設置正確.?-->??

  • ????<context:component-scan?base-package="org.liukai.tutorial"?/>??

  • ??

  • ????<!--?配置注解驅動的Spring?MVC?Controller?的編程模型.注:次標簽只在?Servlet?MVC工作!?-->??

  • ????<mvc:annotation-driven?/>??

  • ??

  • </beans>??






  • 接著是創建JSP頁面?

    commonpage.jsp?

    Jsp代碼??

  • <%@?page?language="java"?contentType="text/html;?charset=UTF-8"??

  • ????pageEncoding="UTF-8"%>??

  • <!DOCTYPE?html?PUBLIC?"-//W3C//DTD?HTML?4.01?Transitional//EN"?"http://www.w3.org/TR/html4/loose.dtd">??

  • <html>??

  • <head>??

  • <meta?http-equiv="Content-Type"?content="text/html;?charset=UTF-8">??

  • <title>Insert?title?here</title>??

  • </head>??

  • <body>??

  • ????<h1>Common?Page</h1>??

  • ????<p>每個人都能訪問的頁面.</p>??

  • ????<a?href="/spring3-security-integration/main/admin">?Go?AdminPage?</a>??

  • ????<br?/>??

  • ????<a?href="/spring3-security-integration/auth/login">退出登錄</a>??

  • ??

  • </body>??

  • </html>??




  • adminpage.jsp?

    Jsp代碼??

  • <%@?page?language="java"?contentType="text/html;?charset=UTF-8"??

  • ????pageEncoding="UTF-8"%>??

  • <!DOCTYPE?html?PUBLIC?"-//W3C//DTD?HTML?4.01?Transitional//EN"?"http://www.w3.org/TR/html4/loose.dtd">??

  • <html>??

  • <head>??

  • <meta?http-equiv="Content-Type"?content="text/html;?charset=UTF-8">??

  • <title>Insert?title?here</title>??

  • </head>??

  • <body>??

  • ????<h1>Admin?Page</h1>??

  • ????<p>管理員頁面</p>??

  • ????<a?href="/spring3-security-integration/auth/login">退出登錄</a>??

  • </body>??

  • </html>??



  • 這兩個JSP對應著?

    ?


    ?


    當然還有登陸頁面和拒絕訪問頁面?

    ?


    ?

    loginpage.jsp?

    Jsp代碼??

  • <%@?taglib?uri="http://java.sun.com/jsp/jstl/core"?prefix="c"%>??

  • <%@?taglib?uri="http://www.springframework.org/tags/form"?prefix="form"%>??

  • <%@?taglib?uri="http://www.springframework.org/tags"?prefix="spring"%>??

  • ??

  • <%@?page?language="java"?contentType="text/html;?charset=UTF-8"??

  • ????pageEncoding="UTF-8"%>??

  • <!DOCTYPE?html?PUBLIC?"-//W3C//DTD?HTML?4.01?Transitional//EN"?"http://www.w3.org/TR/html4/loose.dtd">??

  • <html>??

  • <head>??

  • <meta?http-equiv="Content-Type"?content="text/html;?charset=UTF-8">??

  • <title>Insert?title?here</title>??

  • </head>??

  • <body>??

  • ??

  • ????<h1>Login</h1>??

  • ??

  • ????<div?id="login-error">${error}</div>??

  • ??

  • ????<form?action="../j_spring_security_check"?method="post">??

  • ??

  • ????????<p>??

  • ????????????<label?for="j_username">Username</label>?<input?id="j_username"??

  • ????????????????name="j_username"?type="text"?/>??

  • ????????</p>??

  • ??

  • ????????<p>??

  • ????????????<label?for="j_password">Password</label>?<input?id="j_password"??

  • ????????????????name="j_password"?type="password"?/>??

  • ????????</p>??

  • ??

  • ????????<input?type="submit"?value="Login"?/>??

  • ??

  • ????</form>??

  • ??

  • </body>??

  • </html>??




  • deniedpage.jsp?

    Jsp代碼??

  • <%@?page?language="java"?contentType="text/html;?charset=UTF-8"??

  • ????pageEncoding="UTF-8"%>??

  • <!DOCTYPE?html?PUBLIC?"-//W3C//DTD?HTML?4.01?Transitional//EN"?"http://www.w3.org/TR/html4/loose.dtd">??

  • <html>??

  • <head>??

  • <meta?http-equiv="Content-Type"?content="text/html;?charset=UTF-8">??

  • <title>Insert?title?here</title>??

  • </head>??

  • <body>??

  • ????<h1>你的權限不夠!</h1>??

  • ????<p>只有擁有Admin權限才能訪問!</p>??

  • ????<a?href="/spring3-security-integration/auth/login">退出登錄</a>??

  • </body>??

  • </html>??




  • 還有一個controller用于映射上面兩個JSP頁面..?

    LoginLogoutController.java
    ?

    Java代碼??

  • package?org.liukai.tutorial.controller;??

  • ??

  • import?org.apache.log4j.Logger;??

  • import?org.springframework.stereotype.Controller;??

  • import?org.springframework.ui.ModelMap;??

  • import?org.springframework.web.bind.annotation.RequestMapping;??

  • import?org.springframework.web.bind.annotation.RequestMethod;??

  • import?org.springframework.web.bind.annotation.RequestParam;??

  • ??

  • @Controller??

  • @RequestMapping("auth")??

  • public?class?LoginLogoutController?{??

  • ??

  • ????protected?static?Logger?logger?=?Logger.getLogger("controller");??

  • ??

  • ????/**?

  • ?????*?指向登錄頁面?

  • ?????*/??

  • ????@RequestMapping(value?=?"/login",?method?=?RequestMethod.GET)??

  • ????public?String?getLoginPage(??

  • ????????????@RequestParam(value?=?"error",?required?=?false)?boolean?error,??

  • ????????????ModelMap?model)?{??

  • ??

  • ????????logger.debug("Received?request?to?show?login?page");??

  • ??

  • ????????if?(error?==?true)?{??

  • ????????????//?Assign?an?error?message??

  • ????????????model.put("error",??

  • ????????????????????"You?have?entered?an?invalid?username?or?password!");??

  • ????????}?else?{??

  • ????????????model.put("error",?"");??

  • ????????}??

  • ????????return?"loginpage";??

  • ??

  • ????}??

  • ??

  • ????/**?

  • ?????*?指定無訪問額權限頁面?

  • ?????*??

  • ?????*?@return?

  • ?????*/??

  • ????@RequestMapping(value?=?"/denied",?method?=?RequestMethod.GET)??

  • ????public?String?getDeniedPage()?{??

  • ??

  • ????????logger.debug("Received?request?to?show?denied?page");??

  • ??

  • ????????return?"deniedpage";??

  • ??

  • ????}??

  • }??



  • 該controller實現了兩個映射?

    引用

    auth/login???? --顯示Login頁面?
    auth/denied??? --顯示拒絕訪問頁面




    最后,讓我們看看spring-security.xml的配置?

    spring-security.xml?

    Xml代碼??

  • <?xml?version="1.0"?encoding="UTF-8"?>??

  • <beans?xmlns="http://www.springframework.org/schema/beans"??

  • ????xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"???

  • ????xmlns:security="http://www.springframework.org/schema/security"??

  • ????xsi:schemaLocation="http://www.springframework.org/schema/beans???

  • ????????????http://www.springframework.org/schema/beans/spring-beans-3.0.xsd??

  • ????????????http://www.springframework.org/schema/security???

  • ????????????http://www.springframework.org/schema/security/spring-security-3.0.xsd">??

  • ??????

  • ????<!--??Spring-Security?的配置?-->??

  • ????<!--?注意開啟use-expressions.表示開啟表達式.??

  • ????see:http://www.family168.com/tutorial/springsecurity3/html/el-access.html??

  • ?????-->??

  • ????<security:http?auto-config="true"?use-expressions="true"?access-denied-page="/auth/denied"?>??

  • ??????????

  • ????????<security:intercept-url?pattern="/auth/login"?access="permitAll"/>??

  • ????????<security:intercept-url?pattern="/main/admin"?access="hasRole('ROLE_ADMIN')"/>??

  • ????????<security:intercept-url?pattern="/main/common"?access="hasRole('ROLE_USER')"/>??

  • ??????????

  • ????????<security:form-login??

  • ????????????????login-page="/auth/login"???

  • ????????????????authentication-failure-url="/auth/login?error=true"???

  • ????????????????default-target-url="/main/common"/>??

  • ??????????????

  • ????????<security:logout???

  • ????????????????invalidate-session="true"???

  • ????????????????logout-success-url="/auth/login"???

  • ????????????????logout-url="/auth/logout"/>??

  • ??????

  • ????</security:http>??

  • ??????

  • ????<!--?指定一個自定義的authentication-manager?:customUserDetailsService?-->??

  • ????<security:authentication-manager>??

  • ????????????<security:authentication-provider?user-service-ref="customUserDetailsService">??

  • ????????????????????<security:password-encoder?ref="passwordEncoder"/>??

  • ????????????</security:authentication-provider>??

  • ????</security:authentication-manager>??

  • ??????

  • ????<!--?對密碼進行MD5編碼?-->??

  • ????<bean?class="org.springframework.security.authentication.encoding.Md5PasswordEncoder"?id="passwordEncoder"/>??

  • ??

  • ????<!--???

  • ????????通過?customUserDetailsService,Spring會自動的用戶的訪問級別.??

  • ????????也可以理解成:以后我們和數據庫操作就是通過customUserDetailsService來進行關聯.??

  • ?????-->??

  • ????<bean?id="customUserDetailsService"?class="org.liukai.tutorial.service.CustomUserDetailsService"/>??

  • ??????

  • </beans>??





  • 在配置中我們可以看到三個URL對應的三個權限?

    Xml代碼??

  • <security:intercept-url?pattern="/auth/login"?access="permitAll"/>??

  • ????????<security:intercept-url?pattern="/main/admin"?access="hasRole('ROLE_ADMIN')"/>??

  • ????????<security:intercept-url?pattern="/main/common"?access="hasRole('ROLE_USER')"/>??



  • 需要注意的是我們使用了SpringEL表達式來指定角色的訪問.?
    以下是表達式對應的用法.?

    引用


    表達式 說明?
    hasRole([role]) 返回 true 如果當前主體擁有特定角色。?
    hasAnyRole([role1,role2]) 返回 true 如果當前主體擁有任何一個提供的角色 (使用逗號分隔的字符串隊列)?
    principal 允許直接訪問主體對象,表示當前用戶?
    authentication 允許直接訪問當前 Authentication對象 從SecurityContext中獲得?
    permitAll 一直返回true?
    denyAll 一直返回false?
    isAnonymous() 如果用戶是一個匿名登錄的用戶 就會返回 true?
    isRememberMe() 如果用戶是通過remember-me 登錄的用戶 就會返回 true?
    isAuthenticated() 如果用戶不是匿名用戶就會返回true?
    isFullyAuthenticated() 如果用戶不是通過匿名也不是通過remember-me登錄的用戶時, 就會返回true。?



    所以?

    Xml代碼??

  • <security:intercept-url?pattern="/auth/login"?access="permitAll"/>??


  • 表示所有的人都可以訪問/auth/login.?


    Xml代碼??

  • <security:intercept-url?pattern="/main/admin"?access="hasRole('ROLE_ADMIN')"/>??

  • ????????<security:intercept-url?pattern="/main/common"?access="hasRole('ROLE_USER')"/>??


  • 則表示只有擁有對應的角色才能訪問.?





    Xml代碼??

  • <security:form-login??

  • ????????login-page="/auth/login"???

  • ????????authentication-failure-url="/auth/login?error=true"???

  • ????????default-target-url="/main/common"/>??



  • 表示通過 /auth/login這個映射進行登錄.?
    如果驗證失敗則返回一個URL:/auth/login?error=true?
    如果登錄成功則默認指向:/main/common?



    Xml代碼??

  • security:logout???

  • ????????????????invalidate-session="true"???

  • ????????????????logout-success-url="/auth/login"???

  • ????????????????logout-url="/auth/logout"/>??



  • 很簡單.我們開啟了session失效功能.?
    注銷URL為:/auth/logout?
    注銷成功后轉向:/auth/login?


    Xml代碼??

  • <!--?指定一個自定義的authentication-manager?:customUserDetailsService?-->??

  • ????<security:authentication-manager>??

  • ????????????<security:authentication-provider?user-service-ref="customUserDetailsService">??

  • ????????????????????<security:password-encoder?ref="passwordEncoder"/>??

  • ????????????</security:authentication-provider>??

  • ????</security:authentication-manager>??

  • ??????

  • ????<!--?對密碼進行MD5編碼?-->??

  • ????<bean?class="org.springframework.security.authentication.encoding.Md5PasswordEncoder"?id="passwordEncoder"/>??

  • ??

  • ????<!--???

  • ????????通過?customUserDetailsService,Spring會自動的用戶的訪問級別.??

  • ????????也可以理解成:以后我們和數據庫操作就是通過customUserDetailsService來進行關聯.??

  • ?????-->??

  • ????<bean?id="customUserDetailsService"?class="org.liukai.tutorial.service.CustomUserDetailsService"/>??



  • 一個自定義的CustomUserDetailsService,是實現SpringSecurity的UserDetailsService接口,但我們重寫了他即便于我們進行數據庫操作.?



    DbUser.java?

    Java代碼??

  • package?org.liukai.tutorial.domain;??

  • ??

  • public?class?DbUser?{??

  • ??

  • ????private?String?username;??

  • ????private?String?password;??

  • ????private?Integer?access;??

  • ??

  • ?????//getter/setter??

  • ??

  • }??




  • 通過一個初始化的List來模擬數據庫操作.?

    UserDao.java?

    Java代碼??

  • package?org.liukai.tutorial.dao;??

  • ??

  • import?java.util.ArrayList;??

  • import?java.util.List;??

  • ??

  • import?org.apache.log4j.Logger;??

  • import?org.liukai.tutorial.domain.DbUser;??

  • ??

  • public?class?UserDao?{??

  • ??

  • ????protected?static?Logger?logger?=?Logger.getLogger("dao");??

  • ??

  • ????public?DbUser?getDatabase(String?username)?{??

  • ??

  • ????????List<DbUser>?users?=?internalDatabase();??

  • ??

  • ????????for?(DbUser?dbUser?:?users)?{??

  • ????????????if?(dbUser.getUsername().equals(username)?==?true)?{??

  • ????????????????logger.debug("User?found");??

  • ????????????????return?dbUser;??

  • ????????????}??

  • ????????}??

  • ????????logger.error("User?does?not?exist!");??

  • ????????throw?new?RuntimeException("User?does?not?exist!");??

  • ??

  • ????}??

  • ??

  • ????/**?

  • ?????*?初始化數據?

  • ?????*/??

  • ????private?List<DbUser>?internalDatabase()?{??

  • ??

  • ????????List<DbUser>?users?=?new?ArrayList<DbUser>();??

  • ????????DbUser?user?=?null;??

  • ??

  • ????????user?=?new?DbUser();??

  • ????????user.setUsername("admin");??

  • ??

  • ????????//?"admin"經過MD5加密后??

  • ????????user.setPassword("21232f297a57a5a743894a0e4a801fc3");??

  • ????????user.setAccess(1);??

  • ??

  • ????????users.add(user);??

  • ??

  • ????????user?=?new?DbUser();??

  • ????????user.setUsername("user");??

  • ??

  • ????????//?"user"經過MD5加密后??

  • ????????user.setPassword("ee11cbb19052e40b07aac0ca060c23ee");??

  • ????????user.setAccess(2);??

  • ??

  • ????????users.add(user);??

  • ??

  • ????????return?users;??

  • ??

  • ????}??

  • }??




  • 自定義UserDetailsService .可以通過繼承UserDetailsService?
    來達到靈活的自定義UserDetailsService?

    關于UserDetailsService更多信息. 可以查看SpringSecurity3文檔?


    CustomUserDetailsService.java?

    Java代碼??

  • ?package?org.liukai.tutorial.service;??

  • ??

  • import?java.util.ArrayList;??

  • import?java.util.Collection;??

  • import?java.util.List;??

  • ??

  • import?org.apache.log4j.Logger;??

  • import?org.liukai.tutorial.dao.UserDao;??

  • import?org.liukai.tutorial.domain.DbUser;??

  • import?org.springframework.dao.DataAccessException;??

  • import?org.springframework.security.core.GrantedAuthority;??

  • import?org.springframework.security.core.authority.GrantedAuthorityImpl;??

  • import?org.springframework.security.core.userdetails.User;??

  • import?org.springframework.security.core.userdetails.UserDetails;??

  • import?org.springframework.security.core.userdetails.UserDetailsService;??

  • import?org.springframework.security.core.userdetails.UsernameNotFoundException;??

  • ??

  • /**?

  • ?*?一個自定義的service用來和數據庫進行操作.?即以后我們要通過數據庫保存權限.則需要我們繼承UserDetailsService?

  • ?*??

  • ?*?@author?liukai?

  • ?*??

  • ?*/??

  • public?class?CustomUserDetailsService?implements?UserDetailsService?{??

  • ??

  • ????protected?static?Logger?logger?=?Logger.getLogger("service");??

  • ??

  • ????private?UserDao?userDAO?=?new?UserDao();??

  • ??

  • ????public?UserDetails?loadUserByUsername(String?username)??

  • ????????????throws?UsernameNotFoundException,?DataAccessException?{??

  • ??

  • ????????UserDetails?user?=?null;??

  • ??

  • ????????try?{??

  • ??

  • ????????????//?搜索數據庫以匹配用戶登錄名.??

  • ????????????//?我們可以通過dao使用JDBC來訪問數據庫??

  • ????????????DbUser?dbUser?=?userDAO.getDatabase(username);??

  • ??

  • ????????????//?Populate?the?Spring?User?object?with?details?from?the?dbUser??

  • ????????????//?Here?we?just?pass?the?username,?password,?and?access?level??

  • ????????????//?getAuthorities()?will?translate?the?access?level?to?the?correct??

  • ????????????//?role?type??

  • ??

  • ????????????user?=?new?User(dbUser.getUsername(),?dbUser.getPassword()??

  • ????????????????????.toLowerCase(),?true,?true,?true,?true,??

  • ????????????????????getAuthorities(dbUser.getAccess()));??

  • ??

  • ????????}?catch?(Exception?e)?{??

  • ????????????logger.error("Error?in?retrieving?user");??

  • ????????????throw?new?UsernameNotFoundException("Error?in?retrieving?user");??

  • ????????}??

  • ??

  • ????????return?user;??

  • ????}??

  • ??

  • ????/**?

  • ?????*?獲得訪問角色權限?

  • ?????*??

  • ?????*?@param?access?

  • ?????*?@return?

  • ?????*/??

  • ????public?Collection<GrantedAuthority>?getAuthorities(Integer?access)?{??

  • ??

  • ????????List<GrantedAuthority>?authList?=?new?ArrayList<GrantedAuthority>(2);??

  • ??

  • ????????//?所有的用戶默認擁有ROLE_USER權限??

  • ????????logger.debug("Grant?ROLE_USER?to?this?user");??

  • ????????authList.add(new?GrantedAuthorityImpl("ROLE_USER"));??

  • ??

  • ????????//?如果參數access為1.則擁有ROLE_ADMIN權限??

  • ????????if?(access.compareTo(1)?==?0)?{??

  • ????????????logger.debug("Grant?ROLE_ADMIN?to?this?user");??

  • ????????????authList.add(new?GrantedAuthorityImpl("ROLE_ADMIN"));??

  • ????????}??

  • ??

  • ????????return?authList;??

  • ????}??

  • }??



  • 最后啟動服務器輸入:?
    http://localhost:8080/spring3-security-integration/auth/login?



    總結?
    通過本教程.我們對SpringSecurity3有了進一步的認識.?
    主要是了解了UserDetailsService的重要作用.?
    以及實現了模擬自定義數據的登錄.(這點很重要,很多人學習了SpringSecurity卻不知道?
    如何自定義權限)?

    這次教程因為內容很多,顯得比較粗糙.很多地方并沒有詳細的闡明.?
    后面的教程還是SpringSecurity.?
    但我們將對SpringSecurity3新推出的一些特性進行詳細的說明和理解.?


    BTW:附件為本次教程源碼.你可以下載后直接在tomcat或其他web服務器啟動.也可以自行添加?
    maven插件啟動.?

    ?

    ?

    轉載于:https://www.cnblogs.com/hackerxian/p/10871666.html

    總結

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