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[LintCode] strStr [KMP brute force]

發布時間:2025/3/19 编程问答 18 豆豆
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Problem

For a given source string and a target string, you should output the first index(from 0) of target string in source string.

If target does not exist in source, just return -1.

Note

我終于找到了比較好的KMP算法。
http://alice-alicesspace.blogspot.com/2015/07/strstr-kmp-solution-java.html

Solution

class Solution {public int strStr(String source, String target) {//write your code hereif (source == null | target == null) {return -1;}int i, j;for (i = 0; i < source.length() - target.length() +1; i++) {for (j = 0; j < target.length(); j++) {if (source.charAt(i+j) != target.charAt(j)) {break;}}if (j == target.length()) {return i;}}return -1;} }

KMP算法不如也貼出來。

class Solution {public int strStr(String source, String target) {//write your code hereif (source == null || target == null) {return -1;}if (target.length() == 0) {return 0;}int[] prefix = new int[target.length()];int k = 0;for (int i = 1; i < target.length(); i++) {while (k > 1 && target.charAt(k) != target.charAt(i)) {k = prefix[k-1];}if (target.charAt(i) == target.charAt(k)) k++;prefix[i] = k;}k = 0;for (int i = 0; i < source.length(); i++) {while (k > 1 && source.charAt(i) != target.charAt(k)) {k = prefix[k-1];}if (target.charAt(k) == source.charAt(i)) {k++;}if (k == target.length()) {return i - k + 1;}}return -1;} }

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