要求：獲得按table1_id分組，并且age最大的記錄信息，即2、3、5條 方法一： select * from (select * from table2 order by age desc) as a group by a.table1_id 方法二： select a.* from table2 as a where age = (select max(age) from table2 where a.table1_id=table1_id) 方法三： select a.* from table2 as a where not exists (select * from table2 where table1_id=a.table1_id and age>a.age) 方法四： select a.* from table2 as a where exists (select count(*) from table2 where table1_id=a.table1_id and age>a.age having count(*)=0)

轉(zhuǎn)載于:https://www.cnblogs.com/xiaowufile/p/6888899.html

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