題目描寫敘述

On a broken keyboard, some of the keys are worn out. So when you type some sentences, the characters corresponding to those keys will not appear on screen.Now given a string that you are supposed to type, and the string that you actually type out, please list those keys which are for sure worn out.

輸入描寫敘述:

Each input file contains one test case. For each case, the 1st line contains the original string, and the 2nd line contains the typed-out string. Each string contains no more than 80 characters which are either English letters [A-Z] (case insensitive), digital numbers [0-9], or "_" (representing the space). It is guaranteed that both strings are non-empty.

輸出描寫敘述:

For each test case, print in one line the keys that are worn out, in the order of being detected. The English letters must be capitalized. Each worn out key must be printed once only. It is guaranteed that there is at least one worn out key.

輸入樣例:

7_This_is_a_test_hs_s_a_es

輸出樣例:

7TI

#include<iostream> #include <cstring> #include <cstdlib> #include <string>using namespace std;const int MAX=80;//去掉字符串中反復的字符 void Remove(char* s, int num) {int i,j,l;i=j=0;for(i=0;i<num;i++){for(l=0;l<j;l++){if(s[l]==s[i])break;}if(l>=j){s[j++]=s[i];}}s[j]='\0'; }//找出第1個字符串中，沒有在第2個字符串中出現的字符。 void Worn(char* lhs, char* rhs, char* result) {int i,j,k;k=0;for(i=0;lhs[i]!='\0';i++){for(j=0;rhs[j]!='\0';j++){if(lhs[i]==rhs[j])break;}if(rhs[j]=='\0'){result[k++]=lhs[i];}}result[k]='\0'; }int main() {int i;string n,m;char sn[MAX],sm[MAX],sr[MAX];while(cin>>n>>m){//將輸入的字符串1中的小寫英文字符轉換為大寫英文字符for(i=0;i<n.length();i++){sn[i]=n[i];if((sn[i]>=65)&&(sn[i]<=90) || (sn[i]>=97)&&(sn[i]<=122))sn[i]=::toupper(sn[i]);}sn[i]='\0';//將輸入的字符串2中的小寫英文字符轉換為大寫英文字符for(i=0;i<m.length();i++){sm[i]=m[i];if((sm[i]>=65)&&(sm[i]<=90) || (sm[i]>=97)&&(sm[i]<=122))sm[i]=::toupper(sm[i]);}sm[i]='\0';/*for(i=0;sn[i]!='\0';i++)cout<<sn[i]<<" ";cout<<endl;for(i=0;sm[i]!='\0';i++)cout<<sm[i]<<" ";cout<<endl; */Remove(sn,n.length());Remove(sm,m.length());Worn(sn,sm,sr);for(i=0;sr[i]!='\0';i++)cout<<sr[i];cout<<endl;}return 0; }

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