?比如有一個(gè)數(shù)，需要兩個(gè)線(xiàn)程對(duì)其交替操作，代碼如下

public class ThreadDemo {public static void main(String[] args) {Message message = new Message();Runnable adder = new Adder(message);Runnable suber = new Suber(message);Thread thread1 = new Thread(adder, "adder");Thread thread2 = new Thread(suber, "suber");thread1.start();thread2.start();} }class Adder implements Runnable {private Message msg;public Adder(Message message){this.msg=message;}@Overridepublic void run() {for(int i = 0 ; i < 5;i++){msg.add();}} }class Suber implements Runnable {private Message msg;public Suber(Message message){this.msg=message;}@Overridepublic void run() {for(int i = 0 ; i < 5 ;i++){msg.sub();}} }class Message{private int num;private boolean flag;public Message() {this.num =0;this.flag = true;//flag ==true 加 flag ==false 減}public synchronized void add() {if(!flag){try {super.wait();} catch (InterruptedException e) {e.printStackTrace();}}num++;System.out.println(Thread.currentThread().getName()+",num:"+num);flag = false;this.notifyAll();}public synchronized void sub(){if(flag){try {super.wait();} catch (InterruptedException e) {e.printStackTrace();}}num--;System.out.println(Thread.currentThread().getName()+",num:"+num);flag = true;this.notifyAll();} }

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