I want count the same elements of two lists. Lists can have duplicate elements, so I can't convert this to sets and use & operator.

a=[2,2,1,1]

b=[1,1,3,3]

set(a) & set(b) work

a & b don't work

It is possible to do it withoud set and dictonary?

解決方案

In Python 3.x (and Python 2.7, when it's released), you can use collections.Counter for this:

>>> from collections import Counter

>>> list((Counter([2,2,1,1]) & Counter([1,3,3,1])).elements())

[1, 1]

Here's an alternative using collections.defaultdict (available in Python 2.5 and later). It has the nice property that the order of the result is deterministic (it essentially corresponds to the order of the second list).

from collections import defaultdict

def list_intersection(list1, list2):

bag = defaultdict(int)

for elt in list1:

bag[elt] += 1

result = []

for elt in list2:

if elt in bag:

# remove elt from bag, making sure

# that bag counts are kept positive

if bag[elt] == 1:

del bag[elt]

else:

bag[elt] -= 1

result.append(elt)

return result

For both these solutions, the number of occurrences of any given element x in the output list is the minimum of the numbers of occurrences of x in the two input lists. It's not clear from your question whether this is the behavior that you want.

總結

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