两个各四只青蛙过河java_趣味算法——青蛙过河(JAVA)
/*** 青蛙過河
*@authorrubekid
**/
public classRiverFrog {public static final int LEFT_FROG = -1;public static final int RIGHT_FROG = 1;public static final int STONE = 0;private int[] frogs;private intzeroIndex;private intlength;private int step = 0;public RiverFrog(intnumber) {
frogs= new int[number * 2 +1];
length=frogs.length;
zeroIndex= length /2;for(int i=0; i< number; i++){
frogs[i]=LEFT_FROG;
}
frogs[zeroIndex]=STONE;for(int i=0; i< number; i++){
frogs[i+ zeroIndex + 1] =RIGHT_FROG;
}
}public voidrun(){while(!isMoveEnd(LEFT_FROG) || !isMoveEnd(RIGHT_FROG)){int left = zeroIndex - 1;int right = zeroIndex+1;if(left>-1 && right 0 && frogs[left-1] == RIGHT_FROG){//若移動right，則在中間有兩只RIGHT并排
this.move(right);
}else{this.move(left);
}
}else if(left > 0 && frogs[left-1]==LEFT_FROG ){this.move(left-1);
}else if(right <= length && frogs[right+1] ==RIGHT_FROG){this.move(right+1);
}
}else{if(frogs[left] ==RIGHT_FROG){if(left > 0 && frogs[left-1] ==LEFT_FROG){this.move(left - 1);
}else if(right+1 < length && frogs[right+1] ==RIGHT_FROG){this.move(right+1);
}else if(frogs[right] ==RIGHT_FROG){this.move(right);
}
}else if(frogs[right] ==LEFT_FROG){if(right+1 < length && frogs[right+1] ==RIGHT_FROG){this.move(right + 1);
}else if(left >0 && frogs[left-1] ==LEFT_FROG){this.move(left-1);
}else if(frogs[left] ==LEFT_FROG){this.move(left);
}
}
}
}else if(left == -1){if(frogs[right] == LEFT_FROG && right
}else{this.move(right);
}
}else if(right ==length){if(frogs[left] == RIGHT_FROG && left > 0){this.move(left-1);
}else{this.move(left);
}
}
}
System.out.println("step:" +step);
}private void move(inti){int temp =frogs[i];
frogs[i]=frogs[zeroIndex];
frogs[zeroIndex]=temp;
zeroIndex=i;
step++;
print();
}private boolean isMoveEnd(intvalue){int i=0; int max=zeroIndex;if(value ==LEFT_FROG){
i= zeroIndex+1;
max=length;
}for(int j=i; j
}
}return true;
}private voidprint(){
StringBuffer stringBuffer= newStringBuffer();for(intfrog : frogs){if(frog>-1){
stringBuffer.append(" " +frog + " ");
}else{
stringBuffer.append(frog+ " ");
}
}
System.out.println(stringBuffer.toString());
}
}
總結(jié)
以上是生活随笔為你收集整理的两个各四只青蛙过河java_趣味算法——青蛙过河(JAVA)的全部內(nèi)容，希望文章能夠幫你解決所遇到的問題。
- 上一篇： java记事本应用程序_Java教程:使
- 下一篇： Java输入光标在printf前面_C+