其實本來是要reverse一下list的，就去查了一下list[::-1]是什么意思，發現還有很多要注意的地方，所以就記一下。

主要是參照https://docs.python.org/3/library/stdtypes.html?highlight=list#list

首先Sequence type有三種

list

tuple

range

slice

[i:j:k]表示的是slice of s from i to j with step k, 對三種類型都有用

>>> a = [1, 2, 3]

>>> a[::-1]

[3, 2, 1]

>>> a = (1, 2, 3)

>>> a[::-1]

(3, 2, 1)

>>> a = range(3)

>>> a[::-1]

range(2, -1, -1)

range中參數是range(start, stop[, step])

initialize a list

s * n表示的是n shallow copies of s concatenated

注意是淺拷貝哦，所以會有如下情況

>>> lists = [[]] * 3

>>> lists

[[], [], []]

>>> lists[0].append(3)

>>> lists

[[3], [3], [3]]

如果元素不是對象的話就沒關系

>>> lists = [0] * 3

>>> lists

[0, 0, 0]

>>> lists[0] = 1

>>> lists

[1, 0, 0]

正確的初始化嵌套list的方法應該是

>>> lists = [[] for i in range(3)]

>>> lists[0].append(3)

>>> lists[1].append(5)

>>> lists[2].append(7)

>>> lists

[[3], [5], [7]]

concatenation pitfall

(感覺還是英文說的清楚些，這一點跟Java是一樣的)

Concatenating immutable sequences always results in a new object. This means that building up a sequence by repeated concatenation will have a quadratic runtime cost in the total sequence length. To get a linear runtime cost, you must switch to one of the alternatives below:

總結

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