1.有參裝飾器

基本版

def auth(argv):def wrapper(f):def inner(*args,**kwargs):f(*args,**kwargs)return innerreturn wrapper

示例:

login_dic = {"username": None, "flag": False} msg = """請選擇app: QQ 微信 抖音 郵箱 """chose = input(msg).upper() def auth(argv):def wrapper(f):def inner(*args,**kwargs):if login_dic["flag"]:f(*args,**kwargs)else:if argv == "QQ":print("歡迎登陸QQ")user = input("請輸入賬號:")password = input("請輸入密碼:")if user == "alex" and password == "alex123":login_dic["flag"] = Truelogin_dic["username"] = userf(*args,**kwargs)else:print("賬號或者密碼錯誤")elif argv == "微信":print("歡迎登陸微信")user = input("請輸入賬號:")password = input("請輸入密碼:")if user == "alex123" and password == "alex123456":login_dic["flag"] = Truelogin_dic["username"] = userf(*args, **kwargs)else:print("賬號或者密碼錯誤")elif argv == "抖音":print("歡迎登陸抖音")user = input("請輸入賬號:")password = input("請輸入密碼:")if user == "alex456" and password == "alex456123":login_dic["flag"] = Truelogin_dic["username"] = userf(*args, **kwargs)else:print("賬號或者密碼錯誤")else:print("歡迎登陸郵箱")user = input("請輸入賬號:")password = input("請輸入密碼:")if user == "alex@qq.com" and password == "alex123":login_dic["flag"] = Truelogin_dic["username"] = userf(*args, **kwargs)else:print("賬號或者密碼錯誤")return innerreturn wrapper@auth(chose) def foo():print("這是一個被裝飾的函數") foo()# @auth(chose) 相等于以下兩行代碼的解構 # wrapper = auth(chose) # foo = wrapper(foo)

2.多個裝飾器裝飾一個函數

''' 遇到問題沒人解答？小編創建了一個Python學習交流QQ群：778463939 尋找有志同道合的小伙伴，互幫互助,群里還有不錯的視頻學習教程和PDF電子書！ ''' def wrapper1(func):def inner1(*args,**kwargs):print(1)func(*args,**kwargs)print(11)return inner1def wrapper2(func):def inner2(*args,**kwargs):print(2)func(*args,**kwargs)print(22)return inner2def wrapper3(func):def inner3(*args,**kwargs):print(3)func(*args,**kwargs)print(33)return inner3@wrapper3 @wrapper2 @wrapper1 def foo():print("這是一個被裝飾的函數")foo()#3 2 1 這是一個被裝飾的函數 11 22 33 與50位技術專家面對面20年技術見證，附贈技術全景圖

總結

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