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第二周 第七节 列表的使用

發布時間:2025/3/20 编程问答 37 豆豆
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name=["zhangyang","guyun","xiangpeng"] print(name[0],name[2])zhangyang xiangpeng name=["zhangyang","guyun","xiangpeng"]  print(name[1:3]) #切片,起始位置包括,結束位置不包括,顧頭不顧尾 "zhangyang","guyun","xiangpeng"

  

name=["zhangyang","guyun","xiangpeng"] print(name[-1])#取最后一個,從右開始數,負號代表從右開始的方向,xiangpeng

  

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name=["zhangyang","guyun","xiangpeng"] print(name[-2]) guyun

  

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取最后兩個值 name=["zhangyang","guyun","xiangpeng","xia"] print(name[-1:-3]) 取值是空 [] 因為切片是從左向右數,這里是-的,所以寫的要從右往左數

  

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取最后兩個值 name=["zhangyang","guyun","xiangpeng","xia"] print(name[-3:-1]) #要最后兩個,冒號左邊從哪里開始,右邊是。負號是從右邊開始,顧首不顧尾['guyun', 'xiangpeng']

  

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name=["zhangyang","guyun","xiangpeng","xia"] print(name[-2:]) #要最后兩個,冒號左邊從哪里開始,右邊是['xiangpeng', 'xia'] 把-1省略掉才能取出來

  

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name=["zhangyang","guyun","xiangpeng","xia"] print(name[0:3]) //可以省略0 print(name[:3])['zhangyang', 'guyun', 'xiangpeng'] 顧首不顧尾

  

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追加: name=["zhangyang","guyun","xiangpeng","xia"] name.append("lei") print(name)['zhangyang', 'guyun', 'xiangpeng', 'xia', 'lei']

  

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插入: name=["zhangyang","guyun","xiangpeng","xia"] name.append("lei") name.insert(1,"chen")#chen的位置就是1 name.insert(3,"xin") #插入位置,每次只能插入一個 print(name)['zhangyang', 'chen', 'guyun', 'xin', 'xiangpeng', 'xia', 'lei']

  

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修改name=["zhangyang","guyun","xiangpeng","xia"] name[2]="xied" print(name)['zhangyang', 'guyun', 'xied', 'xia']

  

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刪除: 法1 name=["zhangyang","guyun","xiangpeng","xia"] name.remove("xia") print(name)['zhangyang', 'guyun', 'xiangpeng']

  

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法2 name=["zhangyang","guyun","xiangpeng","xia"] del name[3] print(name)['zhangyang', 'guyun', 'xiangpeng']

  

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name=["zhangyang","guyun","xiangpeng","xia"] name.pop() 不輸下標,代表刪除最后一個 print(name) ['zhangyang', 'guyun', 'xiangpeng']

  

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name=["zhangyang","guyun","xiangpeng","xia"] name.pop(2) 刪除指定位置 print(name)['zhangyang', 'guyun', 'xia']

  

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name=["zhangyang","guyun","xiangpeng","xia"] print(name.index("guyun"))索引 1

  

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name=["zhangyang","guyun","xiangpeng","xia"] print(name[name.index("guyun")])guyun 把所在的位置的名字打印出來

  

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name=["zhangyang","guyun","guyun","xiangpeng","xia"] print(name.count("guyun")) #統計有多少個guyun2

  

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name=["zhangyang","guyun","guyun","xiangpeng","xia"] name.clear() 清除 print(name) []

  

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name=["zhangyang","guyun","guyun","xiangpeng","xia"] name.reverse() 翻轉 print(name)['xia', 'xiangpeng', 'guyun', 'guyun', 'zhangyang']

  

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name=["zhangyang","guyun","guyun","xiangpeng","xia"] name.sort()排序 print(name)['guyun', 'guyun', 'xia', 'xiangpeng', 'zhangyang']

  

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name=["zhangyang","guyun","guyun","xiangpeng","xia"] name2=[1,2,3,4] name.extend(name2) 合并,并且name2還存在 print(name)['zhangyang', 'guyun', 'guyun', 'xiangpeng', 'xia', 1, 2, 3, 4] [1, 2, 3, 4]

  

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name=["zhangyang","guyun","guyun","xiangpeng","xia"] name2=name.copy()復制 print(name) print(name2)['zhangyang', 'guyun', 'guyun', 'xiangpeng', 'xia'] ['zhangyang', 'guyun', 'guyun', 'xiangpeng', 'xia']

  

轉載于:https://www.cnblogs.com/googlewang/p/10704574.html

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