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MySQL各部门求最值_mysql 求分组最大值的十个解法

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mysql 求分組最大值的十個(gè)解法

發(fā)布時(shí)間:2020-08-08 23:32:28

來(lái)源:51CTO

閱讀:1383

作者:努力的C

"How to solve the same problem in 10 different ways".

One of the common problems to solve in SQL is "Get row with the group-wise maximum". Getting just the maximum for the group is simple, getting the full row which is belonging to the maximum is the interesting step.

求每個(gè)分組的最大值也許簡(jiǎn)單,但是求出對(duì)應(yīng)的最大值的所有信息卻是一個(gè)非常有意思的話題。

SELECT MAX(population), continent

FROM Country

GROUP BY continent;

+-----------------+---------------+

| MAX(population) | continent |

+-----------------+---------------+

| 1277558000 | Asia |

| 146934000 | Europe |

| 278357000 | North America |

| 111506000 | Africa |

| 18886000 | Oceania |

| 0 | Antarctica |

| 170115000 | South America |

+-----------------+---------------+

We use the 'world' database from the MySQL manual for the examples.

我們?cè)囉昧薓ySQL手冊(cè)中的‘world’數(shù)據(jù)庫(kù)作為測(cè)試

The next step is to find the countries which have the population and the continent of our gathered data.

下面我們就可以找到一條數(shù)據(jù)對(duì)應(yīng)的全部數(shù)據(jù)

***SELECT continent, name, population

FROM Country

WHERE population = 1277558000

AND continent = 'Asia';

+-----------+-------+------------+

| continent | name | population |

+-----------+-------+------------+

| Asia | China | 1277558000 |

+-----------+-------+------------+

Instead of doing this row by row we just do a JOIN between the two by using a temporary table:

為避免一行一行的搜索,我們可以建一個(gè)臨時(shí)表,然后使用join操作

CREATE TEMPORARY TABLE co2

SELECT continent, MAX(population) AS maxpop

FROM Country

GROUP BY continent;

SELECT co1.continent, co1.name, co1.population

FROM Country AS co1, co2

WHERE co2.continent = co1.continent

AND co1.population = co2.maxpop;*

+---------------+----------------------------------------------+------------+

| continent | name | population |

+---------------+----------------------------------------------+------------+

| Oceania | Australia | 18886000 |

| South America | Brazil | 170115000 |

| Asia | China | 1277558000 |

| Africa | Nigeria | 111506000 |

| Europe | Russian Federation | 146934000 |

| North America | United States | 278357000 |

| Antarctica | Antarctica | 0 |

| Antarctica | Bouvet Island | 0 |

| Antarctica | South Georgia and the South Sandwich Islands | 0 |

| Antarctica | Heard Island and McDonald Islands | 0 |

| Antarctica | French Southern territories | 0 |

+---------------+----------------------------------------------+------------+

DROP TEMPORARY TABLE co2;

刪除臨時(shí)表;

Instead of using a temporary table as internal steps we can write the same also as simple sub-query which is creating a temporary table internally.

當(dāng)然了,我們也可以使用子查詢代替臨時(shí)表

*SELECT co1.continent, co1.name, co1.population

FROM Country AS co1,

(SELECT continent, MAX(population) AS maxpop

FROM Country

GROUP BY continent) AS co2

WHERE co2.continent = co1.continent

and co1.population = co2.maxpop;***

+---------------+----------------------------------------------+------------+

| continent | name | population |

+---------------+----------------------------------------------+------------+

| Oceania | Australia | 18886000 |

| South America | Brazil | 170115000 |

| Asia | China | 1277558000 |

| Africa | Nigeria | 111506000 |

| Europe | Russian Federation | 146934000 |

| North America | United States | 278357000 |

| Antarctica | Antarctica | 0 |

| Antarctica | Bouvet Island | 0 |

| Antarctica | South Georgia and the South Sandwich Islands | 0 |

| Antarctica | Heard Island and McDonald Islands | 0 |

| Antarctica | French Southern territories | 0 |

+---------------+----------------------------------------------+------------+

The sub-query is executed in the exact same way as the temporary table we created by hand. Instead of JOINing against the temporary table we JOIN against the result of the sub-query.

Hmm, this was too simple ? Let's take a look at the alternatives:

SELECT co1.continent, co1.name, co1.population

FROM Country AS co1

WHERE co1.population =

(SELECT MAX(population) AS maxpop

FROM Country AS co2

WHERE co2.continent = co1.continent);

To be read as: 'Get the countries which have the same population as the maximum population of the current country'. Using such a sub-qeury results in more readable sub-queries. BUT ... they a 'DEPENDENT' as the inner query is refering to a field of the outer query. This means that for each row of the outer query the inner query is executed.

The same query can be written in two other ways:

SELECT continent, name, population

FROM Country

WHERE ROW(population, continent) IN (

SELECT MAX(population), continent

FROM Country

GROUP BY continent);

SELECT co1.continent, co1.name, co1.population

FROM country as co1

WHERE co1.population >= ALL

(SELECT co2.population

FROM country AS co2

WHERE co2.continent = co1.continent);

If you don't want to use sub-queries and prefer pure JOINs perhaps there are for you:

SELECT co1.continent, co1.name, co1.population

FROM country AS co1 LEFT JOIN country AS co2

ON co1.population < co2.population AND

co1.continent = co2.continent

WHERE co2.population is NULL;

SELECT co1.Continent, co1.Name

FROM Country AS co1 JOIN Country AS co2

ON co2.Continent = co1.Continent AND

co1.Population <= co2.Population

GROUP BY co1.Continent, co1.Name

HAVING COUNT(*) = 1

added 2005-05-28 as no. 11, sent in by rudy@r937.com

SELECT co1.continent, co1.name

FROM Country AS co1 JOIN Country AS co2

ON co1.continent = co2.continent

GROUP BY co1.continent, co1.name

HAVING co1.population = MAX(co2.population)

Now you already know 8 ways. The last two shall only give you some more ideas. First of all a way that doesn't work (yet).

SELECT co2.continent, MAX(co2.population) AS maxpop,

(SELECT name

FROM Country

WHERE population = maxpop AND

continent = co2.continent)

FROM Country AS co2

GROUP BY co2.continent;

ERROR 1247 (42S22): Reference 'maxpop' not supported (reference to group function)

And as the last one the modified max-concat example from the manual.

SELECT continent,

SUBSTRING( MAX( CONCAT(LPAD(population,10,'0'),name) ), 10+1) AS name,

MAX( population ) AS population

FROM Country

GROUP BY continent;

The result is slightly different but it is more about the idea.

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