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栈的应用就进匹配_笔记

發(fā)布時(shí)間:2025/3/20 编程问答 18 豆豆
生活随笔 收集整理的這篇文章主要介紹了 栈的应用就进匹配_笔记 小編覺得挺不錯(cuò)的,現(xiàn)在分享給大家,幫大家做個(gè)參考.

1+2+3 aaa)bbbbbb((cccc)
判斷這段字符串中的括號(hào)是否對(duì)上如果沒有對(duì)上是那一個(gè)沒有對(duì)上

  • 判斷他是否是括號(hào)不是就執(zhí)行下一次
  • 匹配到左括號(hào)將它壓入堆棧
  • 匹配到右括號(hào)判斷棧是否為空,空表示右括號(hào)沒有匹配的左括號(hào)
  • 不為空?qǐng)?zhí)行彈棧,如果是左就匹配
  • 判斷此時(shí)的棧如果為空,左括號(hào)沒有匹配的右括號(hào)
  • .h

    //鏈?zhǔn)綏5墓?jié)點(diǎn) typedef struct LINKNODE {struct LINKNODE*next; }LinkNode;//鏈?zhǔn)綏?/span> typedef struct LINKSTACK {LinkNode head;int size;}LinkStack;class linkstack { public:linkstack();~linkstack(); public:LinkStack* Stack;public://入棧void push_back(LinkStack* stack,LinkNode* data);//出棧void pop_back(LinkStack* stack);//返回棧頂元素LinkNode* Top_LinkStack(LinkStack* stack);//返回棧元素的個(gè)數(shù)int Size_LinkStack(LinkStack* stack);//清空棧void Clear_LinkStack(LinkStack* stack);};

    .cpp

    linkstack::linkstack() {Stack = new LinkStack;Stack->head.next = NULL;Stack->size = 0; }linkstack::~linkstack() {if (Stack == NULL){return;}delete Stack;}//入棧 void linkstack::push_back(LinkStack* stack, LinkNode* data) {if (stack == NULL || data == NULL){return;}data->next = stack->head.next;stack->head.next = data;stack->size++; }//出棧 void linkstack::pop_back(LinkStack* stack) {if (stack == NULL || stack->size == 0){return;}LinkNode* pNext = stack->head.next;stack->head.next = pNext->next;stack->size--; }//返回棧頂元素 LinkNode* linkstack::Top_LinkStack(LinkStack* stack) {if (stack == NULL || stack->size == 0){return NULL;}return stack->head.next; }//返回棧元素的個(gè)數(shù) int linkstack::Size_LinkStack(LinkStack* stack) {if (stack == NULL ){return -1;}return stack->size; }//清空棧 void linkstack::Clear_LinkStack(LinkStack* stack) {if (stack == NULL || stack->size == 0){return;}stack->head.next = NULL;stack->size = 0; }

    main.cpp

    typedef struct MYCHAR {LinkNode node;char* pAddress;int index;}MyChar;int IsLeft( char c) {return c == '('; }int IsRight(char c) {return c == ')'; }MyChar* CreateMyChar(char* p,int index) {MyChar* mychar = new MyChar;mychar->pAddress = p;mychar->index = index;return mychar; }void ShowError(char* str,int pos) {cout << str << endl;for (int i = 0; i < pos; i++){cout << " ";}cout << "A"; }int main() {char* str = "1+2+3(aaabbbbbb(cccc)";char* p = str;int index = 0;linkstack* l = new linkstack();while (*p != '\0'){//如果是左括號(hào) 直接進(jìn)棧if (IsLeft(*p)){l->push_back(l->Stack, (LinkNode*)CreateMyChar(p,index));}//如果是右括號(hào) 從棧頂彈出元素 if (IsRight(*p)){if (l->Size_LinkStack(l->Stack) >0){MyChar* mychar = (MyChar*)l->Top_LinkStack(l->Stack);if (IsLeft(*mychar->pAddress)){l->pop_back(l->Stack);delete mychar;}}else{cout << "右括號(hào)沒有匹配的左括號(hào)"<<endl;ShowError(str,index);break;}}p++;index++;}while (l->Size_LinkStack(l->Stack) > 0){MyChar* mychar = (MyChar*)l->Top_LinkStack(l->Stack);cout << "左括號(hào)沒有匹配的右括號(hào)"<<endl;ShowError(str,mychar->index);l->pop_back(l->Stack);delete mychar;}delete l;return 0; }

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