ida反編譯：
調用了6個函數對輸入的字符串進行了加密，進入func1看看：
對輸入的57個字符進行了xor
接下來進入xfun1:
很明顯對前10個進行了xor,后面的函數幾個同理。
接下來寫python腳本解密：

data=[0x15,0x1F,0x12,0x14,0x08,0x3A,0x46,0x2C,0x07,0x1B,0x51,0x13,0x3F,0x57,0x08,0x05,0x3F,0x30,0x32,0x51,0x52,0x02,0x6E,0x78,0x16,0x7C,0x6E,0x61,0x70,0x48,0x1C,0x3B,0x32,0x2A,0x13,0x45,0x07,0x2A,0x18,0x0C,0x6E,0x41,0x70,0x04,0x06,0x6E,0x5C,0x00,0x42,0x45,0x70,0x5A,0x02,0x04,0x0E,0x4C] print len(data) for i in range(0,16):data[i+40]^=0xef for i in range(0,10):data[i+30]^=0xab for i in range(0,10):data[i+20]^=0xef for i in range(0,10):data[i+10]^=0xbe for i in range(0,10):data[i]^=0xad for i in range(0,56):data[i]^=0xdedata=[chr(x) for x in data] print ''.join(data)

總結

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