題目描述:

題目鏈接:https://www.luogu.com.cn/problem/P1424

代碼實例:

一開始想的比較復雜，先展示比較復雜的

方法一:

public class Main {public static void main(String[] args) {Scanner scanner = new Scanner(System.in);int x = scanner.nextInt();//表示從周x算起int n = scanner.nextInt();//經過n天int sum = 0;for (int i = 1; i <= 7; i++) {if(x==i) {if(n-(7-x+1)<=5) {sum = ((5-i)+1)*250+250*(n-(7-x+1));}else{if((n-(7-x+1))%7>=1 && (n-(7-x+1))%7<=5) {sum = ((5-i)+1)*250+(n-(7-x+1))/7*5*250+(n-(7-x+1))%7*250;}else if((n-(7-x+1))%7>5 && (n-(7-x+1))%7<=7 || (n-(7-x+1))%7==0){sum = ((5-i)+1)*250+(n-(7-x+1))/7*5*250;}}}if(i==7 && x==7) {if((n-1)%7<=5) {sum = ((n-1)/7)*5*250+((n-1)%7)*250;}else if((n-1)%7==0) {sum = ((n-1)/7)*5*250;}else if((n-1)%7<=5) {sum = ((n-1)/7)*5*250+(n-1)%7*250;}else if((n-1)%7>5 && (n-1)%7<=7 ) {sum = ((n-1)/7)*5*250+5*250;}}if(i==6 && x==6) {if((n-2)/7<=5) {sum = ((n-2)/7)*5*250+((n-2)/7)*250;}else {sum = ((n-2)/7)*5*250+5*250;}}}System.out.println(sum);scanner.close();}}

簡便的
方法二:

public class Main{public static void main(String args[]) {Scanner scanner = new Scanner (System.in);int xingqi = scanner.nextInt();int day = scanner.nextInt();int sum = 0;for (int i = 0; i < day; i++) {if(xingqi!=6 && xingqi!=7) {sum += 250;}if(xingqi==7) {xingqi = 1;}else {xingqi++;}}System.out.println(sum);scanner.close();} }

總結

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