Java集合:数组的使用
Java中對Array數組的常用操作
目錄:
備注:文內代碼具有關聯性。
1.聲明數組;
| 1 2 3 4 | String [] arr; int?arr1[]; String[] array=new?String[5]; int?score[]=new?int[3]; |
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2.初始化數組;
| 1 2 3 4 5 6 7 8 9 10 | //靜態初始化 int?arr2[]=new?int[]{1,2,3,4,5}; String[] array1={"馬超","馬云","關羽","劉備","張飛"}; String[] array2=new?String[]{"黃渤","張藝興","孫紅雷","小豬","牙哥","黃磊"}; int?score[]=new?int[3]; //動態初始化 for(int?i=0;i<score.length;i++) {??? score[i]=i+1;? } |
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3.查看數組長度;
| 1 2 | int?length=array1.length; System.out.println("length:? "+array1.length); |
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4.遍歷數組;
| 1 2 3 | for?(int?i =?0; i < array1.length; i++) { ????System.out.println(array1[i]); } |
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5.int數組轉成string數組;
| 1 2 3 | int[]? array3={1,2,3,4,5,6,7,8,9,0}; ????????String arrStrings=Arrays.toString(array3); ????????System.out.println(arrStrings); |
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?6.從array中創建arraylist;
| 1 2 | ArrayList<String> arrayList=new?ArrayList<String>(Arrays.asList(array1)); System.out.println(arrayList); |
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7.數組中是否包含某一個值;
| 1 2 3 4 5 | String a="馬超"; String[] array1={"馬超","馬云","關羽","劉備","張飛"}; if?(Arrays.asList(array1).contains(a)) { ????System.out.println("馬超在這里"); } |
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8.將數組轉成set集合;
| 1 2 3 | String[] array2=new?String[]{"黃渤","張藝興","孫紅雷","小豬","牙哥","黃磊"}; ????Set<String> set=new?HashSet<String>(Arrays.asList(array2)); ????System.out.println(set); |
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9.將數組轉成list集合;
| 1 2 3 4 5 6 7 8 9 10 11 | String[] array2=new?String[]{"黃渤","張藝興","孫紅雷","小豬","牙哥","黃磊"}; //方法 1. List<String> list=new?ArrayList<String>(); for?(int?i =?0; i < array2.length; i++) { ????list.add(array2[i]); } ? String[] arrStrings2={"1","2","3"}; //方法 2. List<String > list2=java.util.Arrays.asList(arrStrings2); System.out.println(list2); |
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10.Arrays.fill()填充數組;
| 1 2 3 4 5 6 | int[] arr3=new?int[5]; ????????Arrays.fill(arr3,?10);??//將數組全部填充10 ???????????????//遍歷輸出 ????????for?(int?i =?0; i < arr3.length; i++) { ????????????System.out.println(arr3[i]); ????????} |
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11.數組排序;
| 1 2 3 4 5 6 7 8 9 10 11 12 | //方法 1. int[] arr4 = {3,?7,?2,?1,?9}; Arrays.sort(arr4);?????????//.sort(int[] a)?? 放入數組名字 for?(int?i =?0; i < arr4.length; i++) { ????System.out.println(arr4[i]); } //方法 2.???????? int[] arr5 = {3,?7,?2,?1,?9,3,45,7,8,8,3,2,65,34,5}; Arrays.sort(arr5,?1,?4);??//.sort(a, fromIndex, toIndex)??? 從第幾個到第幾個之間的進行排序 for?(int?i =?0; i < arr5.length; i++) { ????????System.out.println(arr5[i]); } |
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12.復制數組;
| 1 2 3 4 5 6 7 8 | //方法 1. int[] arr6 = {3,?7,?2,?1}; int[] arr7=Arrays.copyOf(arr6,?10);??//指定新數組的長度 //方法 2.???????? int[] arr8=Arrays.copyOfRange(arr6,?1,?3);?//只復制從索引[1]到索引[3]之間的元素(不包括索引[3]的元素) for?(int?i =?0; i < arr8.length; i++) { ????????System.out.println(arr8[i]); } |
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13.比較兩個數組;
| 1 2 3 | int[] arr9 = {1,?2,?3,?4,5,6,7,8,9,0}; ????????boolean?arr10=Arrays.equals(arr6, arr9); ????????System.out.println(arr10); |
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14.去重復;
| 1 2 3 4 5 6 7 8 9 10 11 12 13 | int[] arr11 = {1,?2,?3,?4,5,6,7,8,9,0,3,2,4,5,6,7,4,32,2,1,1,4,6,3}; //利用set的特性 Set<Integer> set2=new?HashSet<Integer>(); for?(int?i =?0; i < arr11.length; i++) { ????set2.add(arr11[i]); } System.out.println(set2); int[] arr12 =?new?int[set2.size()]; int?j=0; for?(Integer i:set2) { ????arr12[j++]=i; } System.out.println(Arrays.toString(arr12)); |
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15.查詢數組中的最大值和最小值;
| 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 | int[] arr11 = {10,?2,?3,?4,5,6,7,8,9,0,3,2,4,5,6,7,4,32,2,1,1,4,6,3}; ?//計算最大值 int?max = arr11[0]; for?(int?i =?1; i < arr11.length; i++) { ?????if?(arr11[i] > max) { ?????????max = arr11[i]; ????} ??} ??System.out.println("Max is "?+ max); ??//計算最小值 ??int?min = arr11[0]; ??for?(int?i =?0; i < arr11.length; i++) { ????if?(arr11[i]<min) { ????????min = arr11[i]; ????} } ??System.out.println("Min is "?+ min); |
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