新建一個ServerForPOSTMethod的動態網站工程

新建一個servlert??? ServerForPOSTMethod.java

import java.io.IOException; import javax.servlet.ServletException; import javax.servlet.annotation.WebServlet; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse;/*** Servlet implementation class ServerForPOSTMethod*/ @WebServlet("/ServerForPOSTMethod") public class ServerForPOSTMethod extends HttpServlet {private static final long serialVersionUID = 1L;/*** @see HttpServlet#HttpServlet()*/public ServerForPOSTMethod() {super();// TODO Auto-generated constructor stub}/*** @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)*/protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {// TODO Auto-generated method stub}/*** @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)*/protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {// TODO Auto-generated method stubString name= request.getParameter("name");String age= request.getParameter("age");System.out.println("name from POST method: " + name );System.out.println("age from POST method: " + age );}}

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打開curl

輸入

$ curl --silent -d 'name=www&age=200' 'http://localhost:8080/ServerForPOSTMethod/ServerForPOSTMethod'

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轉載于:https://www.cnblogs.com/yuliyang/p/3747566.html

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