leetcode -eleven:Container With Most Water
2019獨(dú)角獸企業(yè)重金招聘Python工程師標(biāo)準(zhǔn)>>>
????Given?n?non-negative integers?a1,?a2, ...,?an, where each represents a point at coordinate (i,?ai).?n?vertical lines are drawn such that the two endpoints of line?i?is at (i,?ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.
Note: You may not slant the container.
????大致意思就是從給定數(shù)組中取出任意兩個(gè)數(shù),作垂直于X軸的直線和X軸組成一個(gè)容器,求這個(gè)容器裝滿水最大的可能值。
解法一:直接采用遍歷的方法,時(shí)間復(fù)雜度O(n2),提交上去超時(shí)
解法二:從兩邊往中間遍歷,總是移動(dòng)較小的那個(gè)邊,時(shí)間復(fù)雜度O(n)。代碼如下:
public?class?Solution?{public?int?maxArea(int[]?height)?{int?left=0,right=height.length-1;int?max=0,w,h,index;while(left<right){w=right-left;h=height[left]>height[right]?height[right]:height[left];if(max<(w*h))max=w*h;if(height[left]<height[right]){index=left;index++;while?(index<right?&&?height[left]>=height[index])index++;left=index;}else?{index=right;index--;while?(index>left?&&?height[right]>=height[index]?)index--;right=index;}}return?max;} }轉(zhuǎn)載于:https://my.oschina.net/endeavour/blog/490950
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