日韩性视频-久久久蜜桃-www中文字幕-在线中文字幕av-亚洲欧美一区二区三区四区-撸久久-香蕉视频一区-久久无码精品丰满人妻-国产高潮av-激情福利社-日韩av网址大全-国产精品久久999-日本五十路在线-性欧美在线-久久99精品波多结衣一区-男女午夜免费视频-黑人极品ⅴideos精品欧美棵-人人妻人人澡人人爽精品欧美一区-日韩一区在线看-欧美a级在线免费观看

歡迎訪問 生活随笔!

生活随笔

當(dāng)前位置: 首頁 >

【LeetCode从零单排】No129 Sum Root to Leaf Numbers

發(fā)布時間:2025/4/5 31 豆豆
生活随笔 收集整理的這篇文章主要介紹了 【LeetCode从零单排】No129 Sum Root to Leaf Numbers 小編覺得挺不錯的,現(xiàn)在分享給大家,幫大家做個參考.

題目

Given a binary tree containing digits from?0-9?only, each root-to-leaf path could represent a number.

An example is the root-to-leaf path?1->2->3?which represents the number?123.

Find the total sum of all root-to-leaf numbers.

For example,

1/ \2 3

The root-to-leaf path?1->2?represents the number?12.
The root-to-leaf path?1->3?represents the number?13.

Return the sum = 12 + 13 =?25.

代碼

/*** Definition for binary tree* public class TreeNode {* int val;* TreeNode left;* TreeNode right;* TreeNode(int x) { val = x; }* }*/ public class Solution {public int sumNumbers(TreeNode root) {return sum(root, 0); }public int sum(TreeNode n, int s){if (n == null) return 0;if (n.right == null && n.left == null) return s*10 + n.val;return sum(n.left, s*10 + n.val) + sum(n.right, s*10 + n.val); } }


代碼下載:https://github.com/jimenbian/GarvinLeetCode


/********************************

* 本文來自博客 ?“李博Garvin“

* 轉(zhuǎn)載請標(biāo)明出處:http://blog.csdn.net/buptgshengod

******************************************/



總結(jié)

以上是生活随笔為你收集整理的【LeetCode从零单排】No129 Sum Root to Leaf Numbers的全部內(nèi)容,希望文章能夠幫你解決所遇到的問題。

如果覺得生活随笔網(wǎng)站內(nèi)容還不錯,歡迎將生活随笔推薦給好友。