文章目錄

• 1 存儲組件實現思路
• • 1.1 存儲方式的選擇
  • 1.2 stm32的存儲冷知識
  • 1.3 eeprom存儲數據結構設計
  • 1.4 存儲組件操作流程
• 2 代碼實現

1 存儲組件實現思路

1.1 存儲方式的選擇

一般存儲方案可以分為如下幾種：

stm32l0有內部的eeprom，所以我們更傾向于使用內部的eeprom，并且eeprom也是統一編址，只是使用時需要先解鎖。

1.2 stm32的存儲冷知識

對于stm32f1和stm32l0存儲架構是不一樣的，stm32f1在擦除flash時是不能響應中斷的，而stm32l0擦除時是可以響應中斷的。

1.3 eeprom存儲數據結構設計

1.4 存儲組件操作流程

寫操作：

讀操作：

刪除操作：

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2 代碼實現

app_storage.h：

#ifndef __APP_STORAGE_H #define __APP_STORAGE_H#include <stdbool.h>#define EEPROM_BANK1_BASE (0x08080000UL) #define EEPROM_BANK1_END (0x08080BFFUL) #define EEPROM_BANK1_SIZE 3072 #define EEPROM_BANK2_BASE (0x08080C00UL) #define EEPROM_BANK2_END (0x080817FFUL) #define EEPROM_BANK2_SIZE 3072#define STORAGE_PACK_LEN 64 #define STORAGE_DATA_LEN (STORAGE_PACK_LEN-8) #define STORAGE_PACK_COUNT (EEPROM_BANK2_SIZE/STORAGE_PACK_LEN) #define STORAGE_USED_FLAG 0XA1A2A3A4typedef struct {uint32_t flag;uint16_t name;uint16_t len;uint8_t data[STORAGE_DATA_LEN]; }storage_t;#define STORAGE ((storage_t*)EEPROM_BANK2_BASE)bool storage_write(uint16_t name,uint16_t len,uint8_t* pdata); bool storage_read(uint16_t name,uint16_t* p_len,uint8_t* pdata); bool storage_delete(uint16_t name);#endif

app_storage.c：

#include <stdbool.h> #include <stdint.h> #include <string.h> #include "main.h" #include "app_storage.h"static uint16_t storage_find_null() {for(uint8_t i=0;i<STORAGE_PACK_COUNT;i++){if(STORAGE[i].flag!=STORAGE_USED_FLAG){return i;}}return 0XFFFF; } static uint16_t storage_find_name(uint16_t name) {for(uint8_t i=0;i<STORAGE_PACK_COUNT;i++){if((STORAGE[i].flag==STORAGE_USED_FLAG)&&(STORAGE[i].name==name)){return i;}}return 0XFFFF; }bool storage_write(uint16_t name,uint16_t len,uint8_t* pdata) {uint16_t pack_number;if(len>STORAGE_DATA_LEN)return false;pack_number=storage_find_name(name);if(pack_number>=STORAGE_PACK_COUNT){pack_number=storage_find_null();if(pack_number>=STORAGE_PACK_COUNT)return false;} HAL_FLASHEx_DATAEEPROM_Unlock();HAL_FLASHEx_DATAEEPROM_Erase((uint32_t)&STORAGE[pack_number].flag);HAL_FLASHEx_DATAEEPROM_Program(FLASH_TYPEPROGRAMDATA_HALFWORD,(uint32_t)&STORAGE[pack_number].name,name);HAL_FLASHEx_DATAEEPROM_Program(FLASH_TYPEPROGRAMDATA_HALFWORD,(uint32_t)&STORAGE[pack_number].len,len);for(uint8_t i=0;i<len;i++){HAL_FLASHEx_DATAEEPROM_Program(FLASH_TYPEPROGRAMDATA_BYTE,(uint32_t)STORAGE[pack_number].data+i,pdata[i]);}HAL_FLASHEx_DATAEEPROM_Program(FLASH_TYPEPROGRAMDATA_WORD,(uint32_t)&STORAGE[pack_number].flag,STORAGE_USED_FLAG);HAL_FLASHEx_DATAEEPROM_Lock();return true; }bool storage_read(uint16_t name,uint16_t* p_len,uint8_t* pdata) {uint16_t pack_number;pack_number=storage_find_name(name);if(pack_number>=STORAGE_PACK_COUNT)return false;if(*p_len<STORAGE[pack_number].len)return false;memcpy(pdata,STORAGE[pack_number].data,STORAGE[pack_number].len);*p_len=STORAGE[pack_number].len;return true; } bool storage_delete(uint16_t name) {uint16_t pack_number;pack_number=storage_find_name(name);if(pack_number>=STORAGE_PACK_COUNT)return false; HAL_FLASHEx_DATAEEPROM_Unlock();HAL_FLASHEx_DATAEEPROM_Erase((uint32_t)&STORAGE[pack_number].flag);HAL_FLASHEx_DATAEEPROM_Lock(); return true; }

測試代碼如下：

/* USER CODE END Header_StartDefaultTask */ void StartDefaultTask(void const * argument) {/* USER CODE BEGIN StartDefaultTask *//* Infinite loop */float temp,humi;uint8_t write_buf[]="1234567890";uint8_t read_buf[20];uint16_t read_len;#define TEST_NAME 0X0001debug_init();led_init();key_init();led_blink(2,5);sht30_init();for(;;){storage_write(TEST_NAME,sizeof(write_buf),write_buf);memset(read_buf,0,20);read_len=20;if(storage_read(TEST_NAME,&read_len,read_buf)){DEBUG("------%s-----",read_buf);}// if(sht30_get_temp_humi(&temp,&humi))// {// DEBUG("temp=%f,humi=%f",temp,humi);// }osDelay(1000);}/* USER CODE END StartDefaultTask */ } 《新程序員》：云原生和全面數字化實踐50位技術專家共同創作，文字、視頻、音頻交互閱讀

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