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二维树状数组 BZOJ 1452 [JSOI2009]Count

發布時間:2025/4/5 javascript 26 豆豆
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題目鏈接

裸二維樹狀數組

#include <bits/stdc++.h>const int N = 305; struct BIT_2D {int c[105][N][N], n, m;void init(int n, int m) {memset (c, 0, sizeof (c));this->n = n;this->m = m;}void updata(int k, int x, int y, int z) {for (int i=x; i<=n; i+=i&(-i)) {for (int j=y; j<=m; j+=j&(-j)) {c[k][i][j] += z;}}}int query(int k, int x, int y) {int ret = 0;for (int i=x; i; i-=i&(-i)) {for (int j=y; j; j-=j&(-j)) {ret += c[k][i][j];}}return ret;}int count(int x1, int x2, int y1, int y2, int a) {return query (a, x2, y2) - query (a, x2, y1-1) - query (a, x1-1, y2) + query (a, x1-1, y1-1);} };int a[N][N]; BIT_2D bit;int read() {int ret = 0, f = 1;char ch = getchar ();while (ch < '0' || ch > '9') {if (ch == '-') {f = -1;}ch = getchar ();}while (ch >= '0' && ch <= '9') {ret = ret * 10 + ch - '0';ch = getchar ();}return ret * f; }int main() {int n, m;while (scanf ("%d%d", &n, &m) == 2) {bit.init (n, m);for (int i=1; i<=n; ++i) {for (int j=1; j<=m; ++j) {//scanf ("%d", &a[i][j]);a[i][j] = read ();bit.updata (a[i][j], i, j, 1);}}int q;scanf ("%d", &q);while (q--) {int op, x1, x2, y1, y2, x;scanf ("%d", &op);if (op == 1) {//scanf ("%d%d%d", &x1, &y1, &x);x1 = read (); y1 = read (); x = read ();bit.updata (a[x1][y1], x1, y1, -1);a[x1][y1] = x;bit.updata (a[x1][y1], x1, y1, 1);} else {//scanf ("%d%d%d%d%d", &x1, &x2, &y1, &y2, &x);x1 = read (); x2 = read (); y1 = read (); y2 = read (); x = read ();printf ("%d\n", bit.count (x1, x2, y1, y2, x));}}}return 0; }

  

轉載于:https://www.cnblogs.com/Running-Time/p/5503298.html

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