5 Ways to Build Routing in ASP.NET Core

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Bundling in .NET Core MVC Applications with BundlerMinifier.Core

Bundling and minification：微軟文檔

Bundling and Minifying in ASP.NET Core Applications:最簡單易懂

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Custom authorisation policies and requirements in ASP.NET Core

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How to get HttpContext.Current in ASP.NET Core? [duplicate]

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How do I get client IP address in ASP.NET CORE?

Getting the Client’s IP Address in ASP.NET vNext Web Applications

ASP.net Core (RC2): Get IP and Username

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using Static Content Generation in ASP.NET Core

What is the ASP.NET Core MVC equivalent to Request.RequestURI?

How to access ServerVariables in AspnetCore 1.0

How do I apply the OutputCache attribute on a method in a vNext project?

How to use an Area in ASP.NET Core

How to use Areas in Asp.net core 1.0 Rc2 ???#4775

ASP.NET Core 1.0 - Routing - Under the hood

Custom policy-based authorization

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?authorization：授權　　? Authentication：認證

ASP.NET Core 2.0 Authentication and Authorization System Demystified

Authentication example

Walkthrough: ASP.NET MVC Identity with Microsoft Account Authentication

IAuthorizationFilter

Simple Authorization

How do you create a custom AuthorizeAttribute in ASP.NET Core?

ASP.NET Core 2.0 Cookie Authentication

startup example

Authorization in ASP.NET Core: Simple, role, claims-based, and custom

認證系列：cookie認證

認證系列：Authentication原理

認證系列：初識認證

認證系列：OAuth & OpenID Connect認證

認證系列：JwtBearer認證

授權系列：初識授權

授權系列：授權策略是怎么執行的？

授權系列：動態授權

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There is no longer need for MvcHtmlString (which added on top of HtmlString for compatibility reasons) so you can simply use Microsoft.AspNet.Mvc.Rendering.HtmlString.

As you can easily notice, the ViewComponents and Helpers of Asp.Net 5 are also using (by returning) the same HtmlString to the views.

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ASP.Net vnext5 - cannot find JavaScriptSerializer

The syntax of Newtonsoft.Json is very simple.

1. First make sure that you made your class and it's members serializable (e.g. ?use [DataContract] and [DataMember] in your model)

2. Serialize your object to a Json-String:

Newtonsoft.Json.JsonConvert.SerializeObject(yourObject);

3. Deserialize the Json-String:

YourClass yourNewObject = Newtonsoft.Json.JsonConvert.DeserializeObject<YourClass>(jsonString));

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轉載于:https://www.cnblogs.com/panpanwelcome/p/8358739.html

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