鏈接：https://ac.nowcoder.com/acm/contest/123/C
來源：牛客網
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題目描述

There are? cities in Byteland, and the??city has a value?. The cost of building a bidirectional road between two cities is the sum of their values. Please calculate the minimum cost of connecting these cities, which means any two cities can reach each other.

輸入描述:

The first line is an integer? representing the number of test cases.For each test case, the first line is an integer ,? representing the number of cities, the second line are? positive integers?, representing their values.

輸出描述:

For each test case, output an integer, which is the minimum cost of connecting these cities.

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示例1

輸入

復制

2 4 1 2 3 4 1 1

輸出

復制

12 0

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思維題：

題意：將每座城市用公路連接起來，使得城市之間相連，求花費最少的方案（每條路的花費 = 連接兩座城市的和）

思維：用心想想，很明顯這是在構造一個n叉樹，只要確定最小的根節點即可。

#include<cstdio> #include<iostream> #include<algorithm> #include<cstring> #include<string>using namespace std;const int maxn = 1e5+5; const int INF = 1e9+7; int a[maxn];int main() {int n;scanf("%d", &n);int m = INF;for(int i = 0; i < n; i++) scanf("%d", &a[i]);if(n == 1){printf("0");return 0;}sort(a, a+n);int sum = 0;for(int i = 1; i < n; i++) sum += a[i];sum += a[0];printf("%d\n", sum);return 0; }

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