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初始化一個集合

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Backbone的查詢?

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<script>var list = [{title: 'title1',description: 'description1'},{title: 'title2',description: 'description2'},{title: 'title1',description: 'description3'}];var MyList = Backbone.Collection.extend({});var aList = new MyList(list);// var foo = aList.filter(function (model) { //find() 方法 ；filter方法查找多個// return model.get('title') == 'title1';// });var foo=aList.where({title:'title1'})</script>

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Backbone的遍歷

<script>var list = [{title: 'title1',description: 'description1'},{title: 'title2',description: 'description2'},{title: 'title1',description: 'description3'}];var MyList = Backbone.Collection.extend({});var aList = new MyList(list);aList.each(function(model){console.log(model.get('title'));});</script>

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<script>var list = [{title: 'title1',description: 'description1'},{title: 'title2',description: 'description2'},{title: 'title1',description: 'description3'}];var MyList = Backbone.Collection.extend({});var aList = new MyList(list);var foo=aList.every(function (model) {return model.get('title') != null;});</script>

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? //some() 只要model中有一個滿足條件都可以

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<script>var list = [{title: 'title1',description: 'description1'},{title: null,description: 'description2'},{title: 'title1',description: 'description3'}];var MyList = Backbone.Collection.extend({});var aList = new MyList(list);var foo=aList.map(function(model){return model.get('title');});</script>

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<script>var list = [{title: 'title1',description: 'description1'},{title: 'title2',description: 'description2'},{title: 'title3',description: 'description3'}];var MyList = Backbone.Collection.extend({});var aList = new MyList(list);var foo=aList.reduce(function(memo,model,index){return memo+','+model.get('title');},'')</script>

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總結

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