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今天在寫練習的時候，傳值亂碼讓我很頭疼。今天就做個筆記，記錄亂碼的解決辦法。

1.在jsp的頭部配置

<%@ page language="java" contentType="text/html; charset=utf-8" pageEncoding="UTF-8"%>

2.在action層

request.setCharacterEncoding("UTF-8");
?response.setCharacterEncoding("UTF-8");

3.jqueryeasyui傳值時出現亂碼,就要解碼

如我傳的值是userName

$("#loains").datagrid( {
?? ??? ?width :myWidth,
?? ??? ?height : myHeight,
'login.do?action=UserList&userName='+encodeURIComponent(userName)';

action取值：

String userName= urlDecoder.decode(request.getParameter("userName"), "UTF-8");

或者：String userName= new String(request.getParameter("userName").getBytes("ISO8859-1"), "UTF-8");

?

4.配置過濾器

web.xml里面

?<filter>
? <filter-name>encodeFilter</filter-name>
? <filter-class>com.wow.util.EncodeFilter</filter-class>
? <init-param>
? ?<param-name>encode</param-name>
? ?<param-value>UTF-8</param-value>
? </init-param>
?</filter>

?<filter-mapping>
? <filter-name>encodeFilter</filter-name>
? <url-pattern>/*</url-pattern>
?</filter-mapping>

在com.wow.util.EncodeFilter類里面

package com.wow.util;

import javax.servlet.Filter;
import javax.servlet.FilterChain;
import javax.servlet.FilterConfig;
import javax.servlet.ServletRequest;
import javax.servlet.ServletResponse;
import javax.servlet.http.HttpServletRequest;

import org.apache.log4j.Logger;

public class EncodeFilter implements Filter {
?? ?private String encode = "UTF-8";

?? ?public void init(FilterConfig config) {
?? ??? ?this.encode = config.getInitParameter("encode");
?? ?}

?? ?public void doFilter(ServletRequest request, ServletResponse response,
?? ??? ??? ?FilterChain chain) {
?? ??? ?try {
?? ??? ??? ?request.setCharacterEncoding(this.encode);
?? ??? ??? ?response.setCharacterEncoding(this.encode);
?? ??? ??? ?chain.doFilter(request, response);
?? ??? ?} catch (Exception e) {
?? ??? ??? ?if (!(e instanceof java.net.SocketException)) {
?? ??? ??? ??? ?if (request instanceof HttpServletRequest) {
?? ??? ??? ??? ??? ?Logger.getLogger(this.getClass()).error(
?? ??? ??? ??? ??? ??? ??? ?"error request uri:"
?? ??? ??? ??? ??? ??? ??? ??? ??? ?+ ((HttpServletRequest) request)
?? ??? ??? ??? ??? ??? ??? ??? ??? ??? ??? ?.getRequestURI());
?? ??? ??? ??? ?}
?? ??? ??? ??? ?Logger.getLogger(this.getClass()).error(e);
?? ??? ??? ?}
?? ??? ??? ?e.printStackTrace();
?? ??? ?}
?? ?}

?? ?public void destroy() {
?? ?}

}
?

轉載于:https://my.oschina.net/u/3720860/blog/1605312

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